我在下面查询UNION ALL。我只需要修改它,这样它将求和结果。
select count (*)
from BAU_DEAN_USER
where checked_date >= date '2019-03-01' and checked_date < date '2019-03-05'
UNION ALL
select count (*)
from BAU_DEAN_USER_ARCHIVE
where checked_date >= date '2019-03-01' and
checked_date < date '2019-03-05'
答案 0 :(得分:0)
select count (*) from
(select 'a' from
BAU_DEAN_USER where checked_date >= date '2019-03-01' and checked_date < date '2019-03-05'
UNION ALL
select 'a' from BAU_DEAN_USER_ARCHIVE where checked_date >= date '2019-03-01' and checked_date < date '2019-03-05')