示例数据集
table1
如您所见,有两种table2
类型,因此group by应该返回两行。当前,当我添加select t2out.name out_name, t2in.name in_name, t1.other_fields
from table1 t1
join table2 t2out on t2out.id=t1.out_path_id
join table2 t2in on t2in.id=t1.in_path_id
子句
我正在使用location
和car
,试图在某个时间范围内返回某些结果。问题是,当我在@BeforeClass
public static void setUpClass() {
ch.qos.logback.classic.Logger root = (ch.qos.logback.classic.Logger) org.slf4j.LoggerFactory.getLogger("org.apache.http");
root.setLevel(ch.qos.logback.classic.Level.INFO);
//...
}
列上添加id,created_at, status, category, c_sub_category
1, 2019-01-02 16:36:06, closed, Issue, Team 1
2, 2019-01-03 18:36:01, closed, Fix, Team 2
子句时,它缺少结果。 c_sub_category
的类型为whereBetween
Laravel 5.6
和SQLite
是碳实例
whereBetween
此查询应返回两个结果。我按created_at
分组,只有两个created_at
,但目前只返回1个结果
DateTime
此查询没有startDate
子句,返回两个正确的结果
endDate
我尝试过的其他方法也无法返回正确的结果集
{
"startDate": {
"date": "2019-01-01 00:00:00.000000",
"timezone_type": 3,
"timezone": "America/Toronto"
},
"endDate": {
"date": "2019-01-06 23:59:59.999999",
"timezone_type": 3,
"timezone": "America/Toronto"
}
}
答案 0 :(得分:0)
您必须输入长日期格式,而不仅仅是日期
std::vector
答案 1 :(得分:0)
另一个解决方案可能是:
Tickets::where('created_at', '>=','2019-01-01 00:00:00.000000')->where('created_at', '<=','2019-01-06 23:59:59.999999');