我是 Golang 的新手,需要帮助。
在我的 PostgreSQL 数据库中,我有4个表。他们叫:surveys
,questions
,options
和surveys_questions_options
。那就是他们的样子。
调查表:
| survey_id (uuid4) | survey_name (varchar) |
|--------------------------------------|-----------------------|
| 0cf1cf18-d5fd-474e-a8be-754fbdc89720 | April |
| b9fg55d9-n5fy-s7fe-s5bh-856fbdc89720 | May |
问题表:
| question_id (int) | question_text (text) |
|-------------------|------------------------------|
| 1 | What is your favorite color? |
OPTIONS 表:
| option_id (int) | option_text (text) |
|-------------------|--------------------|
| 1 | red |
| 2 | blue |
| 3 | grey |
| 4 | green |
| 5 | brown |
SURVEYS_QUESTIONS_OPTIONS 表合并了前三个表中的数据:
| survey_id | question_id | option_id |
|--------------------------------------|-------------|-----------|
| 0cf1cf18-d5fd-474e-a8be-754fbdc89720 | 1 | 1 |
| 0cf1cf18-d5fd-474e-a8be-754fbdc89720 | 1 | 2 |
| 0cf1cf18-d5fd-474e-a8be-754fbdc89720 | 1 | 3 |
| b9fg55d9-n5fy-s7fe-s5bh-856fbdc89720 | 1 | 3 |
| b9fg55d9-n5fy-s7fe-s5bh-856fbdc89720 | 1 | 4 |
| b9fg55d9-n5fy-s7fe-s5bh-856fbdc89720 | 1 | 5 |
如何在Golang中进行烦人的JSON响应?我使用GORM库。我想要这样的JSON响应:
[
{
"survey_id": "0cf1cf18-d5fd-474e-a8be-754fbdc89720",
"survey_name": "April",
"questions": [
{
"question_id": 1,
"question_text": "What is your favorite color?",
"options": [
{
"option_id": 1,
"option_text": "red"
},
{
"option_id": 2,
"option_text": "blue"
},
{
"option_id": 3,
"option_text": "grey"
},
]
}
]
},
{
"survey_id": "b9fg55d9-n5fy-s7fe-s5bh-856fbdc89720",
"survey_name": "May",
"questions": [
{
"question_id": 1,
"question_text": "What is your favorite color?",
"options": [
{
"option_id": 3,
"option_text": "grey"
},
{
"option_id": 4,
"option_text": "green"
},
{
"option_id": 5,
"option_text": "brown"
},
]
}
]
}
]
我的模型如下:
type Survey struct {
SurveyID string `gorm:"primary_key" json:"survey_id"`
SurveyName string `gorm:"not null" json:"survey_name"`
Questions []Question
}
type Question struct {
QuestionID int `gorm:"primary_key" json:"question_id"`
QuestionText string `gorm:"not null;unique" json:"question_text"`
Options []Option
}
type Option struct {
OptionID int `gorm:"primary_key" json:"option_id"`
OptionText string `gorm:"not null;unique" json:"option_text"`
}
答案 0 :(得分:1)
我不确定GORM的一部分,但是使用JSON时,您还需要在嵌套对象上添加struct标签:
type Survey struct {
...
Questions []Question `json:"questions"`
}
type Question struct {
...
Options []Option `json:"options"`
}
答案 1 :(得分:1)
我们在您的代码中缺少某些范围,因此很难为您指明正确的方向。您是要查询GORM以获得[]Survey
,还是要编组[]Survey
?无论如何,您也应该将标签添加到问题中,如slomek回答。
答案 2 :(得分:0)
但是,请尝试以下操作: 以m2m关系获取嵌套数据
type Survey struct {
gorm.Model
SurveyID string `gorm:"primary_key" json:"survey_id"`
SurveyName string `gorm:"not null" json:"survey_name"`
Questions []*Question `gorm:"many2many:survey_questions;"`
}
surveys := []*model.Survey{}
db := dbSession.Where(&model.Survey{SurveyID: id}).Preload("Questions").Find(&surveys)