Question

我具有从下拉列表中选择ID列表的表结构。可以说以下格式：

id,teacher_id,batch_id,course_id,program_id,depart_id

此字段通过ajax调用保存到数据库。现在，我想获取与此id's

关联的名称

我有一个像这样的功能

public function store(StoreEmployeesRequest $request)
{
   $teacherCourse = TeacherCourse::create($request->all());
}

在这里，创建TeacherCourse之后，我想从表$teacherCourse->teacher_id中获取与TeacherCourse相关的所有值并合并值并以以下格式创建数组：

{
    "id":8,
    "program":"Master of Computer", //with program_id from program table
    "course":"software engineering" //with course_id from course table
},
{
    "id":7,
    "program":"Bachelor of Pharmacy", //with program_id from program table
    "course":"Structure Programing" //with course_id from course table
}

TeacherCourse中的关系

public function course()
{
  return $this->belongsTo(Course::class,'course_id');
}

public function program()
{
  return $this->belongsTo(Program::class,'program_id');
}

我试图使用此操作获取值，但失败了。如何通过从多个表中获取值来创建单个数组？

$teacherCourse = $teachercourse->program->map(function ($program) 
{
    return $program->name;
});

Answer 1

尝试一下：

$teacherCourse = $teachercourse->map(function ($teacherCourse) 
{
    return [ 
             'id' => $teacherCourse->id,
             'program' => $teacherCourse->program()->pluck('name'),
             'course' => $teacherCourse->course()->pluck('name');
           ];
})->toArray();

希望对您有帮助

创建具有多对多关系价值的数据列表

1 个答案: