Question

我正在尝试将员工编号保存为EMP00001格式。我在存储区下的控制器中使用了以下代码，并且遇到了非数值错误。

 $emp = Employee::create($request->all()+
        ['employee_number' => Employee::max('employee_number') + 1 ]);
        $employee_code =  sprintf ("EMP",'%06d');
        $employee_no = ($employee_code +$emp);
        $employee_no->save();

employee_number的MySQL列为varchar。谁能看到我在做什么错？

Answer 1

由于Employee::max('employee_number')返回一个字符串，因此它是varchar列类型，因为您以EMP00001的格式插入它们，所以会引发此类错误。您已经为PHP设置了严格类型，这很好。尝试在主查询之外调用它，提取数字，向其添加数字并执行插入操作：

$num_employee_max = Employee::max('employee_number');
$num_employee = (int)str_replace('EMP', '', $num_employee_max);
$new_num_employee = $num_employee + 1;
$employee_code = sprintf('EMP%06d',$new_num_employee);
 $sanitized values = $request->all(); //do the proper sanitization instead of this

 $emp = Employee::create( $sanitized values +
        ['employee_number' =>  $employee_code]);

注意：避免直接从数据库中的输入中插入未经处理的值。

此外，sprintf（“ EMP”，'％06d'）;什么都没做查看有关sprintf的信息：http://php.net/manual/en/function.sprintf.php

Answer 2

尝试

$emp = Employee::create(array_collapse([
$request->toArray(),
['employee_number' =>  preg_replace("|(\d+)|e",
 "$1+1",Employee::max('employee_number'))]
]));
$employee_code =  sprintf ("EMP",'%06d');
$employee_no = ($employee_code +$emp);
$employee_no->save();

在Laravel中保存员工编号会引发错误A遇到非数值

2 个答案: