我正在尝试将BsonElement
转换为BsonDocument
,所以我可以使用TryGetValue();
。但这需要永远(60ms)!我迫不及待想要一百万个参赛作品。
是否有其他方法可以从BsonValue内部获取值?还是我可以以某种方式显着提高速度?
我需要的是inside2
的唯一列表(结构位于结尾)
现在我要做类似的事情,从数组中获取值。
//Maybe this code right here is not working, but you get the idea
// convert to doc -> get value -> convert to doc -> get value
BsonDocument doc = ...;
BsonValue val1;
doc.TryGetValue("files", out val1);
BsonDocument fileAsDoc = val1.ToBsonDocument();
BsonValue catetgoriesValue;
fileAsDoc.TryGetValue("Categories", out catetgoriesValue);
BsonDocument catAsDoc = catetgoriesValue.ToBsonDocument();
BsonValue data3Value;
catAsDoc.TryGetValue("data3", out data3Value);
BsonDocument data3AsDoc = data3.ToBsonDocument();
foreach(BsonElement inside in data3AsDoc){
//.....
}
这就是我的Bson的组合方式:
{
"_id": ObjectId("1234567890123"),
"language" : "DE",
"files" : [
{
"something" : 10,
"something2" : "something2..",
"Categories" : [
{
"data1" : "1234",
"data2" : "1234",
"data3" : [
{
"inside1" : false,
"inside2" : "this is what i need at the end"
},
{
"inside1" : false,
"inside2" : "this is what i need at the end"
}
]
},
[....]
{
"data1" : "1234",
"data2" : "1234",
"data3" : [
{
"inside1" : false,
"inside2" : "this is what i need at the end"
},
{
"inside1" : false,
"inside2" : "this is what i need at the end"
}
]
}
],
"something3" : "text",
"something4" : "text",
"something5" : "text",
"something6" : "text",
"something7" : "text",
}
]
}