Question

如果存在数据库，我必须连接到数据库，如果不存在，我们必须创建一个具有不同名称的数据库并连接到该数据库。因此，我们需要连接到一个数据库，该数据库的名称将根据上述条件而变化。

我当前的代码如下：

<sites
        jcr:primaryType="nt:unstructured"
        sling:resourceType="granite/ui/components/coral/foundation/form/multifield"
        class="full-width"
        composite="{Boolean}true"
        fieldDescription="Click '+' to add a new page"
        fieldLabel="Sites">
    <field
            jcr:primaryType="nt:unstructured"
            sling:resourceType="granite/ui/components/coral/foundation/container"
            name="./sites">
        <layout
                jcr:primaryType="nt:unstructured"
                sling:resourceType="granite/ui/components/foundation/layouts/fixedcolumns"
                method="absolute"/>
        <items jcr:primaryType="nt:unstructured">
            <column
                    jcr:primaryType="nt:unstructured"
                    sling:resourceType="granite/ui/components/foundation/container">
                <items jcr:primaryType="nt:unstructured">
                    <state
                            jcr:primaryType="nt:unstructured"
                            sling:resourceType="granite/ui/components/coral/foundation/form/textfield"
                            fieldLabel="Site"
                            fieldDescription="Enter name of specific site"
                            name="./site"/>
                    <path
                            jcr:primaryType="nt:unstructured"
                            sling:resourceType="granite/ui/components/coral/foundation/form/textfield"
                            fieldLabel="Path"
                            fieldDescription="Select Path"
                            name="./path"/>
                </items>
            </column>
        </items>
    </field>
</sociallist>

有什么办法可以实现？我们正在使用Postgres 11。

Answer 1

我认为这是一个account = {j: [i, k, l] for i, j, k, l in account} account.pop(number) # del account[number] print(account) {9852560352: ['xyz', 'c', 6000], 6854265891: ['pqr', 's', 7000]}脚本。

您可以在psql中使用条件处理：

psql

可以使用

设置变量

\if :reconnect
\connect xdb
\endif

在相应的分支中。

Answer 2

或者可能：

@IBOutlet weak var userImageScrollView: UIScrollView!
@IBOutlet weak var contentView: UIView!
@IBOutlet weak var questionLabel: UILabel!
@IBOutlet weak var optionA: UIButton!
@IBOutlet weak var optionB: UIButton!
@IBOutlet weak var optionC: UIButton!
@IBOutlet weak var optionD: UIButton!

func setupLayout() {
    userImageScrollView.isPagingEnabled = true
    userImageScrollView.isScrollEnabled = true

    userImageScrollView.addSubview(imageViewA)
    imageViewA.translatesAutoresizingMaskIntoConstraints = false
    imageViewA.widthAnchor.constraint(equalTo: userImageScrollView.widthAnchor).isActive = true
    imageViewA.heightAnchor.constraint(equalTo: userImageScrollView.heightAnchor).isActive = true
    imageViewA.topAnchor.constraint(equalTo: userImageScrollView.topAnchor).isActive = true
    imageViewA.bottomAnchor.constraint(equalTo: userImageScrollView.bottomAnchor).isActive = true
    imageViewA.leftAnchor.constraint(equalTo: userImageScrollView.leftAnchor)
    imageViewA.rightAnchor.constraint(equalTo: imageViewB.leftAnchor)
    imageViewA.contentMode = .scaleAspectFit

    userImageScrollView.addSubview(imageViewB)
    imageViewB.translatesAutoresizingMaskIntoConstraints = false
    imageViewB.widthAnchor.constraint(equalTo: userImageScrollView.widthAnchor).isActive = true
    imageViewB.heightAnchor.constraint(equalTo: userImageScrollView.heightAnchor).isActive = true
    imageViewB.bottomAnchor.constraint(equalTo: userImageScrollView.bottomAnchor).isActive = true
    imageViewB.leftAnchor.constraint(equalTo: imageViewA.rightAnchor)
    imageViewA.rightAnchor.constraint(equalTo: imageViewC.leftAnchor)
    imageViewB.contentMode = .scaleAspectFit

    userImageScrollView.addSubview(imageViewC)
    imageViewC.translatesAutoresizingMaskIntoConstraints = false
    imageViewC.widthAnchor.constraint(equalTo: userImageScrollView.widthAnchor).isActive = true
    imageViewC.heightAnchor.constraint(equalTo: userImageScrollView.heightAnchor).isActive = true
    imageViewC.bottomAnchor.constraint(equalTo: userImageScrollView.bottomAnchor).isActive = true
    imageViewC.leftAnchor.constraint(equalTo: imageViewB.rightAnchor)
    imageViewC.rightAnchor.constraint(equalTo: imageViewD.leftAnchor)
    imageViewC.contentMode = .scaleAspectFit

    userImageScrollView.addSubview(imageViewD)
    imageViewD.translatesAutoresizingMaskIntoConstraints = false
    imageViewD.widthAnchor.constraint(equalTo: userImageScrollView.widthAnchor).isActive = true
    imageViewD.heightAnchor.constraint(equalTo: userImageScrollView.heightAnchor).isActive = true
    imageViewD.bottomAnchor.constraint(equalTo: userImageScrollView.bottomAnchor).isActive = true
    imageViewD.leftAnchor.constraint(equalTo: imageViewC.rightAnchor)
    imageViewD.rightAnchor.constraint(equalTo: userImageScrollView.rightAnchor)
    imageViewD.contentMode = .scaleAspectFit

    self.userImageScrollView.delegate = self
}

从PostgreSQL块有条件地设置dbname

2 个答案: