我有一个名为product
的MySQL表,我希望从该表中按数量递减的顺序检索日期范围内的前3个数据。提供了我的表格
# product_id, stock_id, quantity, stock_timestamp
Product ID9, Stock ID2, 1050, 2019-03-04 07:06:37
Product ID8, Stock ID2, 950, 2019-03-04 07:06:27
Product ID7, Stock ID2, 85000, 2019-03-04 07:06:17
Product ID6, Stock ID1, 750, 2019-03-04 07:06:07
Product ID5, Stock ID1, 65000, 2019-03-04 07:05:57
Product ID4, Stock ID1, 550, 2019-03-04 07:05:47
Product ID3, Stock ID, 450, 2019-03-04 07:05:37
Product ID27, Stock ID5, 1950, 2019-02-28 07:05:17
Product ID26, Stock ID5, 1850, 2019-02-28 07:05:17
Product ID25, Stock ID5, 1750, 2019-02-28 07:05:17
Product ID24, Stock ID4, 211650, 2019-02-24 07:05:17
Product ID23, Stock ID4, 1550, 2019-02-24 07:05:17
Product ID22, Stock ID4, 1450, 2019-02-24 07:05:17
我按照提供的方式编写SQL查询
SELECT * FROM StockHandler.product WHERE stock_timestamp BETWEEN DATE("2019-03-03") AND DATE("2019-03-04") ORDER BY quantity DESC LIMIT 3 ;
我从返回的查询中得到一个空值。我发现SQL中没有错误。那么,如何正确编写呢?
答案 0 :(得分:2)
尝试以下-date()
的{{1}}
stock_timestamp
答案 1 :(得分:1)
尝试不带日期()
SELECT * FROM StockHandler.product
WHERE date(stock_timestamp) BETWEEN '2019-03-03' AND '2019-03-04'
ORDER BY quantity DESC LIMIT 3
答案 2 :(得分:0)
MySql会对待
DATE("2019-03-03") AND DATE("2019-03-04")
为
DATE("2019-03-03 00:00:00") AND DATE("2019-03-04 00:00:00")
您可以使用@ fa06的答案或将时间编辑为
DATE("2019-03-03") AND DATE_ADD('2019-03-04',INTERVAL 1 DAY)