我的程序应该检查凭据(如果存在)创建的“ MyDetails.txt”文件中是否存在,如果是,则允许用户继续进行操作,否则终止。但是,该程序接受传递给它的所有值,然后重写现有数据。 我想找出代码中的错误以及是否有另一种解决方案(验证文件中的凭据)。 下面是该程序的代码。
#include<stdio.h>
#include<string.h>
#include<conio.h>
#include <stdlib.h>
main()
{
FILE *Credentials;
char username[15];
char password[12];
//open file for writing
Credentials =fopen("MyDetails.txt","w");
//check if file exists
if(Credentials == NULL)
{
printf("File does not exist\n");
return;
}
//New User
printf("Enter Username\n");
scanf("%s",&username);
fprintf(Credentials,"Username:%s\n",username);
printf("Enter Password\n");
scanf("%s",&password);
fprintf(Credentials,"Password:%s\n",password);
if(username==username)
{
if(password=password)
{
printf("Login Successfull\n");
printf("\n");
float result;
int choice,num;
printf("Press 1 to Exit\n");
printf("Press 2 to Input Current Reading\n");
printf("Press 3 to Calculate Bill\n");
printf("Press 4 to Make Payment\n");
choice = input();
float current,rate,previous,units,monthly,bill,stand,paid;
switch (choice){
case 1:{
exit(0);
break;
}
case 2:{
printf("Input Current Reading\n");
scanf("%f",¤t);
}
case 3:{
printf("Enter Rate\n");
scanf("%f",&rate);
printf("Enter Previous Reading\n");
scanf("%f",&previous);
units=current-previous;
monthly=units*rate;
bill=150+monthly;
printf("\n Total Bill:%.3f\n",bill);
}
case 4:{
printf ("------PAYMENT------\n");
printf("\n");
printf("Amount To Pay is %.3f",bill);
printf("\n");
printf("Enter Amount\n");
scanf("%f",&paid);
printf("Remaining Balance\n %.3f",bill-paid);
break;
}
}
}
else
{
printf("\n Wrong Password");
}
}
else
{
printf("\n User Doesn't Exist'");
}
return 0;
}
int input()
{
int number;
scanf("%d",&number);
return (number);
}
void output(float number)
{
printf("%f",number);
}
答案 0 :(得分:1)
首先,您将username
与自身进行比较。显然,这将始终是“真实”结果。†
您应该将文件中的用户名读入一个变量,然后用户输入另一个变量,并比较这两个不同变量
第二,您需要了解how to properly compare character arrays。
†有时候这是不正确的,例如比较 NaN 值,但这不是其中之一! < / p>