Question

我有一个静态类，具有以下两种方法：

    public async static void Execute()
    {
        var task = new Task<int>(Work);
        try
        {
            task.Start();
            await task;
            Console.WriteLine("This is not reached");
        }
        catch (Exception e)
        {
            Console.WriteLine("This is not reached");
        }
    }

    static int Work()
    {
        Thread.Sleep(500);
        throw new Exception("Oops");
    }

为什么不通过等待任务来传播异常？

Answer 1

您的代码有几个“缺陷”。我会尽力为您“修复”它们，但这并不是您问题的实际答案；-）

#subreddit to use
subreddit = reddit.subreddit('test')

#summoning the bot
keyphrase = '!repostfinder'

#find comments with keyphrase
for comment in subreddit.stream.comments():
    if keyphrase in comment.body:
        print('Found keyphrase')
        comment.reply('Keyphrase detected')
        print('Replied to comment')

希望这可以为您澄清一点。

要点：

您很少需要“创建”任务
不使用//please use Task, not void, since the framework //might have trouble determining it's completion public async static Task Execute() { // no need here to call a constructor //var task = new Task<int>(Work); try { //no need to explicitly start //task.Start(); await Work(); Console.WriteLine("This is not reached"); } catch (Exception e) { //this Will be reached :-) Console.WriteLine("This is reached"); } } //we can just make this a task :-) static async Task<int> Work() { //no need to await... but in this case we do.. //... since we throw an exception after the wait. await Task.Delay(500); throw new Exception("Jeuh!"); }，而是使用async void
始终async Task进行操作：即：尽可能多地创建自己的异步方法
不一定总是等待：您还可以返回任务。
阅读this guy's posts，它们非常好。

等待任务不会传播异常

1 个答案: