Question

Views.py

class templateList(PermissionRequiredMixin, TemplateView):
    permission_required = 'accounts.template_all'

    def get(self, request, *args, **kwargs):
        #view logic
        print(self.request.user.has_perms('accounts.template_all'))
        return render(request, template_name, context)

accounts / models.py

class User(AbstractBaseUser, PermissionsMixin):
    # some fields here
    class Meta:
        verbose_name = _('user')
        verbose_name_plural = _('users')

        permissions = (
            ("template_all", "access to all templates"),
        )

ViewName .___ mro ____

(<class 'template.views.templateList'>, <class 'django.contrib.auth.mixins.PermissionRequiredMixin'>, <class 'django.contrib.auth.mixins.AccessMixin'>, <class 'django.views.generic.base.TemplateView'>, <class 'django.views.generic.base.TemplateResponseMixin'>, <class 'django.views.generic.base.ContextMixin'>, <class 'django.views.generic.base.View'>, <class 'object'>)

views.py中的

self.request.user.has_perms('accounts.template_all')返回正确的布尔值，但是self.has_permission()每次都返回True。 permission_required无效，即使打印返回假，用户仍然可以看到页面。 self.get_permission_required alos返回正确的值。帮助表示赞赏。

Answer 1

简而言之：PermissionRequiredMixin基类应该放在TemplateView基类之前，这样MRO是正确的，并且调度指向PermissionRequiredMixin的替代。

PermissionRequiredMixin为dispatch(..)方法打了补丁（它添加了额外的检查，以查看用户是否具有适当的权限）。但是，在这里，您按顺序放置了子类，结果是dispatch(..)函数是View类的函数。

实际上，如果我们看一下MRO，就会看到：

>>> ViewName.__mro__
(<class 'ViewName'>, <class 'django.views.generic.base.TemplateView'>, <class 'django.views.generic.base.TemplateResponseMixin'>, <class 'django.views.generic.base.ContextMixin'>, <class 'django.views.generic.base.View'>, <class 'django.contrib.auth.mixins.PermissionRequiredMixin'>, <class 'django.contrib.auth.mixins.AccessMixin'>, <class 'object'>)

，如果我们看一下调用.dispatch(..)时所调用的方法，我们会看到：

>>> ViewName.dispatch
<function View.dispatch at 0x7f169e8f6620>

为了让mixin覆盖原始的.dispatch(..)函数，我们需要将其放在基类中，例如：

# PermissionRequiredMixin is put before TemplateView

class ViewName(PermissionRequiredMixin, TemplateView):
    permission_required = 'accounts.action_all'
    # ...

然后我们看到：

>>> ViewName.__mro__
(<class 'ViewName'>, <class 'django.contrib.auth.mixins.PermissionRequiredMixin'>, <class 'django.contrib.auth.mixins.AccessMixin'>, <class 'django.views.generic.base.TemplateView'>, <class 'django.views.generic.base.TemplateResponseMixin'>, <class 'django.views.generic.base.ContextMixin'>, <class 'django.views.generic.base.View'>, <class 'object'>)
>>> ViewName.dispatch
<function PermissionRequiredMixin.dispatch at 0x7f168b41d620>

django PermissionRequiredMixin权限不起作用

1 个答案: