Question

这是我的数组：

Array
(
[4] => Array
    (
        [0] => stdClass Object
            (
                [name] => fixed
                [total_kms] => 200
            )

    )

[9] => Array
    (
        [0] => stdClass Object
            (
                [name] => Temo
                [total_kms] => 550
            )

    )

[10] => Array
    (
        [0] => stdClass Object
            (
                [name] => mohamed mostafa
                [total_kms] => 1273
            )

    )

[11] => Array
    (
        [0] => stdClass Object
            (
                [name] => ahmed mostafa
                [total_kms] => 1122
            )

    )

    )

我想像此表一样显示此数组，但要将此数组从最高编号到最低编号（仅限3个名称）进行排序

显示名称
显示total_kms
从最高编号到最低编号的顺序
限制使用3个名称（表中应该包含前3个名称的公里数位于顶部）

我在桌子上的代码

<table class="table">
      <h4 class="text-muted">
       Top3 drivers done most kilometers
    </h4>
    <hr>
<tbody>
    <tr>
      <th class="thead-dark">Driver</th>
         for ($i=0; $i < count($driver_kms) ; $i++)
         {
           if ($driver_kms[$i]->name !='')
           {
              <td><?=$driver_kms[$i]->name?></td>
           }
          }
    </tr>

    <tr>
      <th>Kms</th>
         for ($i=0; $i < count($driver_kms) ; $i++)
            {
           if ($driver_kms[$i]->name !='')
           {
              <td><?=$driver_kms[$i]->total_kms?></td>
          }
          }
    </tr>

</tbody>

Answer 1

在单个查询中获得预期结果：

SELECT U.name, SUM(R.meters) 
FROM users U, reservations R 
WHERE U.id = R.driver_id
ORDER BY SUM(R.meters) DESC
LIMIT 3

OR

使用arsort($driver_kms)对数组进行排序，然后将for循环限制为3个元素for ($i = 0; $i < 3; $i++) { ...

Answer 2

替换

$users = User::select('name as driver_name','id as user_id')->get(); 
foreach   ($users as $value) { 
  $driver_kms[$value->user_id] = DB::select("select users.name,SUM(reservations.meters) as total_kms from reservations left outer join  ers on (reservations.driver_id=users.id) where zone_id = $url_or_id and driver_id = $value->user_id and reservations.meters !='' order by SUM(reservations.meters) DESC limit 3");
 } 
 $driver_kms = call_user_func_array('array_merge', $driver_kms);

使用

$driver_kms = DB::select("select users.name, SUM(reservations.meters) as total_kms    
from reservations left outer join users 
on (reservations.driver_id = users.id) 
where zone_id = $url_or_id and reservations.meters !='' 
group by reservations.driver_id
order by SUM(reservations.meters) DESC limit 3");

Answer 3

只需使用http://php.net/manual/en/function.uasort.php 使用回调比较数组元素。

如何从最高编号到最低编号（限3个项目）订购此数组？

3 个答案: