Question

我有以下数组：

 [ 
   { "publication": "" }, 
   { "publication": [ 
       { "author": "Author of Paper", 
         "journal": "Journal of Paper", 
         "title": "Title of Paper" 
       }, 
       { "author": "Author Paper", 
         "journal": "Journal Paper", 
         "title": "Title Paper" } ] }, 
   { "publication": "" }
 ]

我想丢弃空条目并将所有条目推送到具有以下输出的新数组中

[
1: {
"author": "Author of Paper",
"title": "Title of Paper"
"journal": "Journal of Paper"
},
2: {
"author": "Author of Paper",
"title": "Title of Paper"
"journal": "Journal of Paper"
}
]

我将如何实现？

我尝试了以下操作：

     var container = {};
     users = users.map(function(obj) {

 for(i = 0; i < publications.length; ++i) {
 container[i] 
         = { 
            "author": obj.author,
            "title": obj.title,
             "journal": obj.journal,
           }; 
}

Answer 1

您可以使用reduce。在内部请首先减少该值是否正确，然后再将其添加到最终输出中。

let arr =  [{ "publication": "" },{ "publication": [{ "author": "Author of Paper", "journal": "Journal of Paper", "title": "Title of Paper" }, { "author": "Author Paper", "journal": "Journal Paper", "title": "Title Paper" } ] }, { "publication": "" } ]
 
let output = arr.reduce((op, {publication} ) => {
  if(publication){
    op.push(...publication)
  }
  return op
},[])

console.log(output)

Answer 2

您可以使用即将到来的Array#flatMap代替虚假的值。

var array = [{ publication: "" }, { publication: [{ author: "Author of Paper", journal: "Journal of Paper", title: "Title of Paper" }, { author: "Author Paper", journal: "Journal Paper", title: "Title Paper" }] }, { publication: "" }],
    result = array.flatMap(({ publication }) => publication || []);

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 3

使用reduce的解决方案

[/*....*/].reduce((acc, {publication}) => acc.includes(publication) ?  acc : [...acc, publication], [])

根据现有的嵌套值创建新数组-Javascript

3 个答案: