我正在尝试制作一款游戏,玩家必须在迷宫中导航鼠标以找到奶酪块。我在让div移动我想要的方式时遇到了一些麻烦。问题是当您按下向下箭头键(我正在用来测试它的键)时,它不会像我想要的那样以10为增量不断下降。我已经尝试过循环,但整个过程都如此,但我只是想不通如何使之工作。
document.onkeydown = function(key){
if (key.keyCode == 38){
console.log("up");
} else if (key.keyCode == 39){
console.log("right");
} else if (key.keyCode == 37){
console.log("left");
} else if (key.keyCode == 40){
mouse.style.top = 10 + "px";
};
};
答案 0 :(得分:2)
您可以使用Player
对象并修改其x
和y
属性。
还创建一个K
对象,将当前使用的键数字设置为布尔值。
比像requestAnimationFrame
这样的循环内移动播放器:
const Player = {
el: document.getElementById('mouse'),
x: 200,
y: 100,
speed: 2,
move() {
// If no collision with map or tiles... (TODO!)
this.el.style.transform = `translate(${this.x}px, ${this.y}px)`;
}
};
const K = {
fn(ev) {
ev.preventDefault();
const k = ev.which;
if (k >= 37 && k <= 40) K[k] = ev.type === "keydown"; // If is arrow
}
};
const update = () => {
// 1 / Math.sqrt(2) = 0.7071.. (Diagonal)
let dist = K[38] && (K[37] || K[39]) || K[40] && (K[37] || K[39]) ? 0.707 : 1;
dist *= Player.speed;
if (K[37]) Player.x -= dist;
if (K[38]) Player.y -= dist;
if (K[39]) Player.x += dist;
if (K[40]) Player.y += dist;
Player.move();
}
document.addEventListener('keydown', K.fn);
document.addEventListener('keyup', K.fn);
(function engine() {
update();
window.requestAnimationFrame(engine);
}());
#mouse{
position: absolute;
left: 0; top: 0;
width: 20px; height: 20px;
background: #000; border-radius: 50%;
}
Click here to focus, and use arrows
<div id="mouse"></div>
一个更简单的示例,只要按住键(就像键入一样),该元素就会以 Npx 个步骤移动并重复:
const Player = {
el: document.getElementById('mouse'),
x: 0,
y: 0,
step: 10,
move() {
this.el.style.transform = `translate(${this.x}px, ${this.y}px)`;
}
};
const keysHandler = (ev) => {
const k = ev.which;
if (k>=37 && k<=40) {
ev.preventDefault();
({
'37' () {Player.x -= Player.step},
'38' () {Player.y -= Player.step},
'39' () {Player.x += Player.step},
'40' () {Player.y += Player.step},
}[k]());
Player.move();
}
}
document.addEventListener('keydown', keysHandler);
#mouse{
position: absolute;
left: 0; top: 0;
width: 20px; height: 20px;
background: #000; border-radius: 50%;
}
Click here to focus, and use arrows
<div id="mouse"></div>
答案 1 :(得分:0)
您每次都将其设置为10,请使用else if (key.keyCode == 40){
mouse.style.top = parseInt(mouse.style.top.split("px")[0]) + 10 + "px";
}
首先获取该值:
df['newid'] = df['date'].dt.strftime('%Y%m%d')+(df.groupby([df['date'].dt.date,'id']).cumcount()+1).astype(str).str.zfill(6) + '-A'
print(df)
# print
date id newid
0 2019-01-01 10:00:00 1 20190101000001-A
1 2019-01-01 11:00:00 1 20190101000002-A
2 2019-01-01 12:00:00 1 20190101000003-A
3 2019-01-01 19:00:00 2 20190101000001-A
4 2019-01-02 09:00:00 2 20190102000001-A
5 2019-01-02 10:00:00 2 20190102000002-A
6 2019-01-05 15:00:00 3 20190105000001-A
答案 2 :(得分:0)
即使其他答案使用了parseInt
,也最好将变量保留在代码中
var x = 0;
var y = 0;
document.onkeydown = function(key){
if (key.keyCode == 38){
y -= 10;
} else if (key.keyCode == 39){
x += 10;
} else if (key.keyCode == 37){
x -= 10;
} else if (key.keyCode == 40){
y += 10;
};
document.getElementById("block").style.left = x+"px";
document.getElementById("block").style.top = y+"px";
};
#block
{
top: 0;
left: 0;
position: absolute;
width: 30px;
height: 60px;
background: teal;
}
<div id="block">