Question

我有这个SQL查询

查询

Select * from `trees` WHERE id = '1' AND ( `apple`='1' OR `banana` = '1' OR `coconut` = '1' OR `pear` ='1') ;

这是我的桌子可以说

Tree_table

id | apple | banana | coconut | pear|
1     1       1       1           0
2     0       0        1          1
3     1       0        0          1

所以我希望我的素养

apple
banana
coconut

使用SQL查询甚至PHP都可以做到

Answer 1

您需要取消透视数据。在MySQL中，用union all最容易做到：

select tree
from ((select id, 'apple' as tree
       from trees
       where apple = 1
      ) union all
      (select id, 'banana' as tree
       from trees
       where banana = 1
      ) union all
      (select id, 'coconut' as tree
       from trees
       where coconut = 1
      ) union all
      (select id, 'pear' as tree
       from trees
       where pear = 1
      )
     ) t
where id = 1;

根据查询获取表的列名

1 个答案: