Question

我有一个二维列表；即一个包含整数和字符串的嵌套列表。

mylist = [[92, "james"], [88, "john"], [75, "robert"], [80, "michael"], [25, "william"], [54, "david"], [59, "richard"], [74, "charles"], [46, "joseph"], [90, "thomas"], [80, "christopher"]]

我只想找到一种方法来检查字符串，检查它们是否以特定字母开头；说j，将其删除，然后忽略其余不符合此条件的元素。

所需的结果将如下所示：

mylist = [[92, "ames"], [88, "ohn"], [75, "robert"], [80, "michael"], [25, "william"], [54, "david"], [59, "richard"], [74, "charles"], [46, "oseph"], [90, "thomas"], [80, "christo, her"]]

Answer 1

如果我对您的理解正确，这是使用list comprehension的解决方案：

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    <div class="container">
        <img src="https://static.pexels.com/photos/52500/horse-herd-fog-nature-52500.jpeg">
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        <img src="https://static.pexels.com/photos/213399/pexels-photo-213399.jpeg">
        <img src="https://static.pexels.com/photos/158471/ibis-bird-red-animals-158471.jpeg">
        <img src="https://static.pexels.com/photos/133459/pexels-photo-133459.jpeg">
        <img src="https://static.pexels.com/photos/50988/ape-berber-monkeys-mammal-affchen-50988.jpeg">
    </div>

</body>

Answer 2

您可以使用函数lstrip()删除前导字符：

[[i, j.lstrip('j')] for i, j in mylist]

包含字符串和整数的二维列表

2 个答案: