Question

我有一个data.frame，其中有一堆具有唯一ID的行，后跟一个氨基酸序列。我想知道是否有一种方法可以将行分成单独的唯一data.frame。

这里是一个示例

bigdf

>ENSCAFP00000018847.4  
FGHFGHFGHFGHFHFGHFGHFGHFGHFHFGHFGHFHFGHFGHFHFHFHFGTNSEGAFQTA
DLLETSVPSHMPLETQTLSPQTFDWTLILANSNSEAETRDTKTTFPAMEGRAFTKMTPSK
>ENSCAFP00000018847.3  
VCXVNSFRERYTRIOUHFSDAADSSAASAAAAGPVVTANHVEEPAMTPGVRTNSEGAFQTA
DLLETSVPSHMPLETQTLSPQTFDWTLILANSNSEAETRDTKTTFPAMEGRAFTKMTPSK
>ENSCAFP00000018847.2  
ASDASDADASDASDASDASDASSADASASRPGPVVTANHVEEPAMTPGVRTNSEGAFQTA
DLLETSVPSHMPLETQTLSPQTFDWTLILANSNSEAETRDTKTTFPAMEGRAFTKMTPSK
>ENSCAFP00000018847.1  
QWEQWEQWEQWEWQREWRQWEQWRQRQQRERPGPVVTANHVEEPAMTPGVRTNSEGAFQTA
DLLETSVPSHMPLETQTLSPQTFDWTLILANSNSEAETRDTKTTFPAMEGRAFTKMTPSK

如果能将新数据的名称作为它们的ID，那就太好了，所以希望结果看起来像这样

ENSCAFP00000018847.4

>ENSCAFP00000018847.4  
FGHFGHFGHFGHFHFGHFGHFGHFGHFHFGHFGHFHFGHFGHFHFHFHFGTNSEGAFQTA
DLLETSVPSHMPLETQTLSPQTFDWTLILANSNSEAETRDTKTTFPAMEGRAFTKMTPSK

ENSCAFP00000018847.3

>ENSCAFP00000018847.3  
VCXVNSFRERYTRIOUHFSDAADSSAASAAAAGPVVTANHVEEPAMTPGVRTNSEGAFQTA
DLLETSVPSHMPLETQTLSPQTFDWTLILANSNSEAETRDTKTTFPAMEGRAFTKMTPSK

ENSCAFP00000018847.2

>ENSCAFP00000018847.2  
ASDASDADASDASDASDASDASSADASASRPGPVVTANHVEEPAMTPGVRTNSEGAFQTA
DLLETSVPSHMPLETQTLSPQTFDWTLILANSNSEAETRDTKTTFPAMEGRAFTKMTPSK

ENSCAFP00000018847.1

>ENSCAFP00000018847.1 QWEQWEQWEQWEWQREWRQWEQWRQRQQRERPGPVVTANHVEEPAMTPGVRTNSEGAFQTADLLETSVPSHMPLETQTLSPQTFDWTLILANSNSEAETRDTKTTFPAMEGRAFTKMTPSK

我知道这是一件很奇怪的事情，但是需要对数千个不同的氨基酸序列进行操作，所以如果我能找到一种将它们全部拆分成R的方法，那将很酷

dput(df[1:3, c(1)])
c("> ENSCAFP00000018847.4 MFFINIISLIIPILLAVAFLTLVERKVLGYMQLRKGPNIVGPYGLLQPIADAVKLFTKEPLRPLTSSMSMFILAPILALSLALTMWIPLPMPYPLINMNLGVLFMLAMSSLAVYSILWSGWASNSKYALIGALRAVAQTISYEVTLAIILLSVLLMNGSFTLSTLIITQEHMWLIFPAWPLAMMWFISTLAETNRAPFDLTEGESELVSGFNVEYAAGPFALFFLAEYANIIMMNILTTILFFGAFHNPFMPELYSINFTMKTLLLTICFLWIRASYPRFRYDQLMHLLWKNFLPLTLALCMWHVALPIITASIPPQT", 
"> ENSCAFP00000018847.3 MKPPILIIIMATIMTGTMIVMLSSHWLLIWIGFEMNMLAIIPILMKKYNPRAMEASTKYFLTQATASMLLMMGVTINLLYSGQWVISKISNPIASIMMTTALTMKLGLSPFHFWVPEVTQGITLMSGMILLTWQKIAPMSILYQISPSINTNLLMLMALTSVLVGGWGGLNQTQLRKIMAYSSIAHMGWMAAIITYNPTMMVLNLTLYILMTLSTFMLFMLNSSTTTLSLSHMWNKFPLITSMILILMLSLGGLPPLSGFIPKWMIIQELTKNNMIIIPTLMAITALLNLYFYLRLTYSTALTMFPSTNNMKMKWQFEYTKKATLLPPLIITSTMLLPLTPMLSVLD", 
"> ENSCAFP00000018847.2 MFINRWLFSTNHKDIGTLYLLFGAWAGMVGTALSLLIRAELGQPGTLLGDDQIYNVIVTAHAFVMIFFMVMPIMIGGFGNWLVPLMIGAPDMAFPRMNNMSFWLLPPSFLLLLASSMVEAGAGTGWTVYPPLAGNLAHAGASVDLTIFSLHLAGVSSILGAINFITTIINMKPPAMSQYQTPLFVWSVLITAVLLLLSLPVLAAGITMLLTDRNLNTTFFDPAGGGDPILYQHLFWFFGHPEVYILILPGFGMISHIVTYYSGKKEPFGYMGMVWAMMSIGFLGFIVWAHHMFTVGMDVDTRAYFTSATMIIAIPTGVKVFSWLATLHGGNIKWSPAMLWALGFIFLFTVGGLTGIVLANSSLDIVLHDTYYVVAHFHYVLSMGAVFAIMGGFAHWFPLFSGYTLNDTWAKIHFTIMFVGVNMTFFPQHFLGLSGMPRRYSDYPDAYTTWNTVSSMGSFISLTAVMLMIFMIWEAFASKREVAMVELTTTNIEWLHGCPPPYHTFEEPTYVIQK"
)

Answer 1

您可以只在行中使用apply函数和as.data.frame：

mydfs <- apply(df, 1, as.data.frame)

mydfs将是作为单个数据帧的行的列表。请注意，它们将被强制。

Answer 2

您可以将所有行放在数据帧的命名列表中，然后使用list2env()将它们放在全局环境中，如下所示：

dfs <- apply(bigdf, MARGIN = 1, as.data.frame) names(dfs) <- str_sub(bigdf[,1], start = 1, end = 20) list2env(dfs, envir = .GlobalEnv)

如何使data.frame的行成为单独的唯一data.frames

2 个答案: