Question

在这里选择查询enter image description here

select rac_username, rac_profilepicture, tafd_postid, tafd_postcontent, tafd_postimage_source, DATE_FORMAT(tafd_postadded,'%M %d, %Y') tafd_postadded,tafd_imotion, (select count(rpg_actormakeget) from r_post_getyou where rpg_postrelate = tafd_postid and rpg_isremoved = 0) as tafd_igetyoucount, (select count(rpg_postrelate) from r_post_getyou where rpg_postrelate = tafd_postid and rpg_actormakeget = (select rac_accountid from r_account_credentials where rac_username = 'zheuswalker' )) as isliked, (select count(rfc_commentid) from r_feeds_comments where rfc_feedparent = tafd_postid) rfc_commentcount from t_account_feeds inner join r_account_credentials on r_account_credentials.rac_accountid = t_account_feeds.tafd_postcreator  
ORDER BY STR_TO_DATE (tafd_postadded,'%M %d, %Y') ASC

我已经尝试过按desc排序日期，但仍然没有得到预期的结果。我希望日期按升序排列（从最新到最早）。

我也尝试通过此命令（ORDER BY tafd_postadded asc）和see picture对其进行订购，请注意，2019年3月在2018年6月至2018年11月之间

Answer 1

STR_TO_DATE比较字符串，因此正常的情况是，火星在11月之前，因为字母M在字母N之前。

您应该这样做：

ORDER BY tafd_postadded DESC

从最新到最旧的描述
从最早到最新的升序

Answer 2

我在tafd_postadded列上使用了 datetime ，因此在对日期时间进行排序时，我们应该使用UNIX_TIMESTAMP();

select * from table order by UNIX_TIMESTAMP(datetime column) desc

ORDER BY ASC不能使用MYSQL DATETIME STR_TO_DATE

2 个答案: