Question

我想在打字稿中以JSON添加两个嵌套对象。

在下面给出的JSON中，我想在第一个JSON的activityLogs中添加第二个JSON的activityLogs项。

JSON1：

[{"vehicleno":"SV028","devicE_CODE":"8505","activityLogs":
    [{"gpsdate":"01/03/2019","gpstime":"13:40:18"},
     {"gpsdate":"01/03/2019","gpstime":"13:38:18"},
     {"gpsdate":"01/03/2019","gpstime":"13:37:18"}]
}]

JSON2：

[{"vehicleno":"SV028","devicE_CODE":"8505","activityLogs":
    [{"gpsdate":"01/03/2019","gpstime":"13:46:18"},
    {"gpsdate":"01/03/2019","gpstime":"13:43:18"}]
}]

结果：

[{"vehicleno":"SV028","devicE_CODE":"8505","activityLogs":
    [{"gpsdate":"01/03/2019","gpstime":"13:46:18"},
    {"gpsdate":"01/03/2019","gpstime":"13:43:18"},
     {"gpsdate":"01/03/2019","gpstime":"13:40:18"},
    {"gpsdate":"01/03/2019","gpstime":"13:38:18"},
    {"gpsdate":"01/03/2019","gpstime":"13:37:18"}]
}]

我该怎么做？

Answer 1

您可以使用隐式数组方法。

julia> s = """-5.871153289887625082e-01,8.095032986136727615e-01,9.900000000000006573e-01,9.900000000000006573e-01,-9.866066418838319585e-01,-3.138907529596844714e+00,-5.129218106887371675e+00,-4.803915800699462224e+00"""
"-5.871153289887625082e-01,8.095032986136727615e-01,9.900000000000006573e-01,9.900000000000006573e-01,-9.866066418838319585e-01,-3.138907529596844714e+00,-5.129218106887371675e+00,-4.803915800699462224e+00"

julia> CSV.read(IOBuffer(s), header=false)
1×8 DataFrame
│ Row │ Column1   │ Column2  │ Column3  │ Column4  │ Column5   │ Column6  │ Column7  │ Column8  │
│     │ Float64⍰  │ Float64⍰ │ Float64⍰ │ Float64⍰ │ Float64⍰  │ Float64⍰ │ Float64⍰ │ Float64⍰ │
├─────┼───────────┼──────────┼──────────┼──────────┼───────────┼──────────┼──────────┼──────────┤
│ 1   │ -0.587115 │ 0.809503 │ 0.99     │ 0.99     │ -0.986607 │ -3.13891 │ -5.12922 │ -4.80392 │

Answer 2

您可以将push()与点差运算符一起使用，或将concat与重新分配符一起使用：

var JSON1 = [{"vehicleno":"SV028","devicE_CODE":"8505","activityLogs":[{"gpsdate":"01/03/2019","gpstime":"13:40:18"},{"gpsdate":"01/03/2019","gpstime":"13:38:18"},{"gpsdate":"01/03/2019","gpstime":"13:37:18"}]}]
var JSON2 = [{"vehicleno":"SV028","devicE_CODE":"8505","activityLogs":[{"gpsdate":"01/03/2019","gpstime":"13:46:18"},{"gpsdate":"01/03/2019","gpstime":"13:43:18"}]}]

JSON1[0].activityLogs.push(...JSON2[0].activityLogs)

console.log(JSON1)

这假设您的json数组仅包含一个顶级对象。如果不是这种情况，则需要添加有关两个数组如何同步的更多详细信息（例如，vehicleno是否会相同？）。

作为示例，如果vehicleno是两个数组中的唯一标识符，则可以创建JSON1值的查找以及将其推入适当的数组的用途。即使其中包含多辆载具，这也会在JSON1位置进行更新：

var JSON1 = [{"vehicleno":"SV028","devicE_CODE":"8505","activityLogs":[{"gpsdate":"01/03/2019","gpstime":"13:40:18"},{"gpsdate":"01/03/2019","gpstime":"13:38:18"},{"gpsdate":"01/03/2019","gpstime":"13:37:18"}]}]
var JSON2 = [{"vehicleno":"SV028","devicE_CODE":"8505","activityLogs":[{"gpsdate":"01/03/2019","gpstime":"13:46:18"},{"gpsdate":"01/03/2019","gpstime":"13:43:18"}]}]

let lookup = JSON1.reduce((lookup, obj) => {
  lookup[obj.vehicleno] = obj
  return lookup
}, {})

JSON2.forEach(obj => lookup[obj.vehicleno].activityLogs.push(...obj.activityLogs))
console.log(JSON1)

Answer 3

最简单的方法是concat activityLogs：

var arr1 = [{
  "vehicleno": "SV028",
  "devicE_CODE": "8505",
  "activityLogs": [{
      "gpsdate": "01/03/2019",
      "gpstime": "13:40:18"
    },
    {
      "gpsdate": "01/03/2019",
      "gpstime": "13:38:18"
    },
    {
      "gpsdate": "01/03/2019",
      "gpstime": "13:37:18"
    }
  ]
}];
var arr2 = [{
  "vehicleno": "SV028",
  "devicE_CODE": "8505",
  "activityLogs": [{
      "gpsdate": "01/03/2019",
      "gpstime": "13:46:18"
    },
    {
      "gpsdate": "01/03/2019",
      "gpstime": "13:43:18"
    }
  ]
}];
var arr3 = arr1[0].activityLogs.concat(arr2[0].activityLogs);
console.log(arr3);

.as-console-wrapper {
  max-height: 100% !important;
  top: auto;
}

请注意，只有在顶层数组中只有一个对象时，此方法才起作用。

Answer 4

result = json1;
/// result = Object.assign({}, json1); if you don't want to mutate the original json1
result.forEach(elem1 => elem1.activityLogs
    .concat(json2.find(elem2 => elem2.vehicleno === elem1.vehicleno).activityLogs));

通过vehicleno找到匹配的元素，将第二个数组项的activityLog与第一个数组项联系起来。

Answer 5

var json1 = [{"vehicleno":"SV028","devicE_CODE":"8505","activityLogs":
    [{"gpsdate":"01/03/2019","gpstime":"13:40:18"},
     {"gpsdate":"01/03/2019","gpstime":"13:38:18"},
     {"gpsdate":"01/03/2019","gpstime":"13:37:18"}]
},{"vehicleno":"SV02","devicE_CODE":"8505","activityLogs":
    [{"gpsdate":"01/03/2019","gpstime":"13:40:18"},
     {"gpsdate":"01/03/2019","gpstime":"13:38:18"},
     {"gpsdate":"01/03/2019","gpstime":"13:37:18"}]
}]


var json2 = [{"vehicleno":"SV028","devicE_CODE":"8505","activityLogs":
    [{"gpsdate":"01/03/2019","gpstime":"13:46:18"},
    {"gpsdate":"01/03/2019","gpstime":"13:43:18"}]
}];

var jsonCont = json1.concat(json2);

var result = Object.values(jsonCont.reduce((acc, o)=>{
    if(!acc.hasOwnProperty(o['vehicleno'])) {
        acc[o['vehicleno']] = Object.assign({}, o);
    } else {
        acc[o['vehicleno']]['activityLogs'] = acc[o['vehicleno']]['activityLogs'].concat(o['activityLogs']);
    }
    return acc;
}, {}));

console.log(result);

将嵌套的json对象项添加到另一个json项

5 个答案: