如何从该模型中获取对象?

时间:2019-02-28 23:37:36

标签: python django django-models django-rest-framework django-views

我正在尝试创建一个有效的地址模型/视图/ ...,并使该模型正常工作,但是我试图访问其中包含的数据,但该模型不起作用。这是模型:

class Profile(models.Model):
    user = models.OneToOneField(User, on_delete=models.CASCADE)
    nick_name = models.CharField('Nick name', max_length=30, blank=True, default='')
    bio = models.TextField(max_length=500, blank=True)
    image = models.ImageField(default='default.jpg', upload_to='profile_pics')
    # Address = models.ForeignKey('Address', on_delete=models.CASCADE)

    # If we don't have this, it's going to say profile object only
    def __str__(self):
        return self.user.username
        #return f'{self.user.username}'  # it's going to print username Profile

    def save(self, *args, **kwargs):
            super().save(*args, **kwargs)

            img = Image.open(self.image.path)

            if img.height > 300 or img.width > 300:
                output_size = (300, 300)
                img.thumbnail(output_size)
                img.save(self.image.path)


class Address(models.Model):
    users = models.ManyToManyField(Profile, blank=True)
    name = models.CharField(max_length=30)
    address = models.CharField(max_length=50)
    city = models.CharField(max_length=60, default="Miami")
    state = models.CharField(max_length=30, default="Florida")
    zipcode = models.CharField(max_length=5, default="33165")
    country = models.CharField(max_length=50)

    class Meta:
        verbose_name_plural = 'Address'

    def __str__(self):
        return self.name

我正在尝试访问用户可以拥有的所有地址。我尝试过:

# TESTS
allAddresses = Address.objects.all()
print(allAddresses)

对于地址对象,它给了我:<QuerySet [<Address: Elizabeth>, <Address: Work>]>

但是,如果我尝试按用户过滤它,就像这样:

allAddresses = Address.objects.all().filter(users='arturo')
print(allAddresses)

它给我一个错误:invalid literal for int() with base 10: 'arturo'

有人可以引导我获取登录用户的所有地址吗?

非常感谢您!

1 个答案:

答案 0 :(得分:2)

过滤器约束users是指中间多对多表的ID,因此是错误。您应该改为完整指定相关字段,其中userProfile.user字段,而usernameUser.username字段:

allAddresses = Address.objects.all().filter(users__user__username='arturo')