Question

我有：

 s='"Tag":"Football","name":"Mickael A","Played":"10times","Tag":"Basket","name":"Bruce B","Played":"8times","Tag":"Football","name":"John R","Played":"6times",'

我想根据足球和篮筐进行分组，即：

['','"Mickael A","Played":"10times"',
'"Bruce B","Played":"8times",',
'"John R","Played":"6times",']

我尝试过：

s.strip().split(r'"Tag":("Football"|"Basket"),"name":')

但是它不起作用。

Answer 1

分析您的字符串，看来您需要：

re.findall(r'"name":(.*?),(?:"Tag"|$)', s)

其中s是您的字符串。这会找到某事（.*?）后跟"name":并先于,"Tag"或,<end>

的所有情况

完整代码：

import re

s = '"Tag":"Football","name":"Mickael A","Played":"10times","Tag":"Basket","name":"Bruce B","Played":"8times","Tag":"Football","name":"John R","Played":"6times",'

print(re.findall(r'"name":(.*?),(?:"Tag"|$)', s))
# ['"Mickael A","Played":"10times"', '"Bruce B","Played":"8times"', '"John R","Played":"6times"']

Answer 2

您需要使用re库，并将足球和篮球设为非捕获组，这样它们就不会出现在结果中：

import re
re.split(r'"Tag":(?:"Football"|"Basket"),"name":', s)

结果将是：

['', '"Mickael A","Played":"10times",', '"Bruce B","Played":"8times",', '"John R","Played":"6times",']

Answer 3

您可以将以下正则表达式与re.split一起使用：

"Tag":"[^"]+","name":

"Tag":"字面匹配
[^"]+匹配一个或多个非"的字符，即匹配下一个"
","name":字面匹配

您也可以使用非贪婪模式.*?"代替[^"]+：

"Tag":".*?","name":'

示例：

In [486]: s = '"Tag":"Football","name":"Mickael A","Played":"10times","Tag":"Basket","name":"Bruce B","Played":"8times","Tag":"Football","name":"John R","Played":"6times",'

In [487]: re.split(r'"Tag":"[^"]+","name":', s)
Out[487]: 
['',
 '"Mickael A","Played":"10times",',
 '"Bruce B","Played":"8times",',
 '"John R","Played":"6times",']

In [488]: re.split(r'"Tag":".*?","name":', s)
Out[488]: 
['',
 '"Mickael A","Played":"10times",',
 '"Bruce B","Played":"8times",',
 '"John R","Played":"6times",']

Answer 4

re库满足您的需求。

import re

s='"Tag":"Football","name":"Mickael A","Played":"10times","Tag":"Basket","name":"Bruce B","Played":"8times","Tag":"Football","name":"John R","Played":"6times",'
re.split('Football|Basket', s)

它返回

>>> ['"Tag":"',
     '","name":"Mickael A","Played":"10times","Tag":"',
     '","name":"Bruce B","Played":"8times","Tag":"',
     '","name":"John R","Played":"6times",']

Answer 5

更好的方法是构造这个字符串，我假设玩过的名字和比赛（重复的涉及一个人）。在此字典列表之后，您可以轻松地操作数据

s='"Tag":"Football","name":"Mickael A","Played":"10times","Tag":"Basket","name":"Bruce B","Played":"8times","Tag":"Football","name":"John R","Played":"6times",'


l=[]
def fun(s):
 return str('{')+s+str('}')
import ast


k = s.strip().split(',')

for i in range(0,len(k),3):
    dic={}
    if len(k[i].split(':'))==2:
        dic['Tag']=ast.literal_eval(fun(k[i]))['Tag']
        dic['name']=ast.literal_eval(fun(k[i+1]))['name']
        dic['Played']=ast.literal_eval(fun(k[i+2]))['Played']
        l.append(dic)
print(l)
'''
output

[{'Tag': 'Football', 'name': 'Mickael A', 'Played': '10times'}, {'Tag': 'Basket', 'name': 'Bruce B', 'Played': '8times'}, {'Tag': 'Football', 'name': 'John R', 'Played': '6times'}]

'''

Python：使用A或B拆分字符串

5 个答案: