Question

当我执行此操作时：

declare @INP_ITBL_NM_SQL char (64)
Exec('
    select '+@INP_ITBL_NM_SQL+' = 
            concat(LTRIM(RTRIM(a.db_schema_name)),LTRIM(RTRIM(b.Name)))
            from '+@db_and_schema+' as a, '+@split_itbl+' as b
            where b.ID = 2 and a.libname = (select c.Name from 
            '+@split_itbl+' as c where c.ID = 1)
')

我收到以下错误：

信息102，级别15，状态1，第2行在'='附近的语法不正确。

select语句中的变量是临时表，每次运行时都需要更改其名称。

感谢您的帮助！

Answer 1

您收到该错误，是因为您试图将本地变量的值设置为动态SQL中的值。因此，当您打印出该SQL文本时，它看起来就像：

SELECT = concat…

应该使用带有sp_executesql的输出参数来执行此操作。类似于以下内容：

DECLARE @SQL nvarchar(max)
DECLARE @ParamDef nvarchar(200)
DECLARE @INP_ITBL_NM_SQL varchar(100) = ''

SET @ParamDef = N'@INP_ITBL_NM_SQL_OUTPUT varchar(100) OUTPUT';

SET @SQL = N'select @INP_ITBL_NM_SQL_OUTPUT = concat(LTRIM(RTRIM(a.db_schema_name)),LTRIM(RTRIM(b.Name)))
            from '+ @db_and_schema+ ' as a, ' + @split_itbl +' as b
            where b.ID = 2 and a.libname = (select c.Name from 
            '+ @split_itbl +' as c where c.ID = 1)'

EXEC sp_executesql @SQL, @ParamDef, @INP_ITBL_NM_SQL_OUTPUT=@INP_ITBL_NM_SQL OUTPUT;

SELECT @INP_ITBL_NM_SQL

Exec语句中'='附近的语法不正确

1 个答案: