Question

我当前正在使用jQuery.when异步执行不同的请求。问题在于，似乎jQuery。何时等待每个调用完成，然后再运行下一个。

第五次调用等待大约需要几秒钟才能返回，例如当单独执行时需要大约一秒钟来处理。

这是我的通话时间：

jQuery.when(search_engine.fetchBucketOne(), search_engine.fetchBucketTwo(), search_engine.fetchBucketThree(), search_engine.fetchBucketFour(), search_engine.fetchBucketFive())
    .done(function(bucket_one_result, bucket_two_result, bucket_three_result, bucket_four_result, bucket_five_result){
        search_engine.bucket_one = bucket_one_result;
        console.log('search_engine.bucket_one');console.log(search_engine.bucket_one);
        search_engine.bucket_two = bucket_two_result;
        console.log('search_engine.bucket_two');console.log(search_engine.bucket_two);
        search_engine.bucket_three = bucket_three_result;
        console.log('search_engine.bucket_three');console.log(search_engine.bucket_three);
        search_engine.bucket_four = bucket_four_result;
        console.log('search_engine.bucket_four');console.log(search_engine.bucket_four);
        search_engine.bucket_five = bucket_five_result;
        console.log('search_engine.bucket_five');console.log(search_engine.bucket_five);
    });

这是ajax请求：

fetchBucketOne: function() {
    url_params = search_engine.createSearchParams();
    return ($.ajax({
        type: "GET",
        url: "/fetch-bucket-one" + url_params,
        contentType : "application/x-www-form-urlencoded",
    }));
},

fetchBucketTwo: function() {
    url_params = search_engine.createSearchParams();
    return ($.ajax({
        type: "GET",
        url: "/fetch-bucket-two" + url_params,
        contentType : "application/x-www-form-urlencoded",
    }));
},

fetchBucketThree: function() {
    url_params = search_engine.createSearchParams();
    return ($.ajax({
        type: "GET",
        url: "/fetch-bucket-three" + url_params,
        contentType : "application/x-www-form-urlencoded",
    }));
},

fetchBucketFour: function() {
    url_params = search_engine.createSearchParams();
    return ($.ajax({
        type: "GET",
        url: "/fetch-bucket-four" + url_params,
        contentType : "application/x-www-form-urlencoded",
    }));
},

fetchBucketFive: function() {
    url_params = search_engine.createSearchParams();
    return ($.ajax({
        type: "GET",
        url: "/fetch-bucket-five" + url_params,
        contentType : "application/x-www-form-urlencoded",
    }));
},

以下是通过chrome开发工具加载网络的结果的屏幕截图：

谢谢大家的帮助！

Answer 1

我会用另一种方式来处理，我的方法是

search_engine.setResult = function(name, result) {
    search_engine[name] = result;
}
var fetchList = [
    {
    name: "bucket_one",
    url: "/fetch-bucket-one",
    contentType: "application/x-www-form-urlencoded",
    successFunction: "setResult",
  },
  {
    name: "bucket_two",
    url: "/fetch-bucket-two",
    contentType: "application/x-www-form-urlencoded",
    successFunction: "setResult",
  }

]

for(i in fetchList)
{
    var fetchItem = fetchLists[i];
    $.ajax({
    url: fetchItem.url + searchengine.createSearchParams(),
    contentType: fetchItem.contentType,
    success: function(data) {
            searchengine[fetchItem.successFunction](fetchItem.name, data);
    }
  })
}

jQuery.when不执行异步ajax调用时

1 个答案: