Question

我有两个数组。我需要将它们进行如下比较，结果应为bool

Input : 
Example 1
---------
stringArray1 = "one","five"
stringArray2 = "two","one" ,"three","five"
Result = true

Example 2
---------
stringArray1 = "one","five"
stringArray2 = "two","three" ,"four","five"
Result = false (As "one" is not present in array2)

代码：

string[] stringArray1 = getDataTabledFromSP.Columns.Cast<DataColumn>()
    .OrderBy(x => x.ColumnName)
    .Select(x => x.ColumnName)
    .ToArray();

string[] stringArray2 = fetchColumnDetailsOfClientById
    .OrderBy(x => x.ColumnName)
    .Select(myLine => myLine.ColumnName).ToArray();

Answer 1

您可以尝试 set 算术：

 bool result = !stringArray1.Except(stringArray2).Any();

我们从stringArray2中减去 stringArray1，然后检查是否有任何项目（stringArray1中没有stringArray2的项目）。

编辑：如果stringArray1和stringArray2可以具有重复，应将其考虑在内（例如，所有三个 >应该在stringArray2中找到相等的项目：

  bool result = !stringArray1
    .GroupBy(item => item)
    .Select(chunk => Tuple.Create(chunk.Key, chunk.Count()))
    .Concat(stringArray2
       .GroupBy(item => item)
       .Select(chunk => Tuple.Create(chunk.Key, -chunk.Count()))
     )
    .GroupBy(item => item.Item1)
    .Select(chunk => chunk.Sum(item => item.Item2))
    .Any(item => item > 0);

Answer 2

因此，当true包含stringArray2中的每个项目时，您是否想要返回stringArray1的东西？应该这样做：

// Not any string which is not contained in the stringArray2
!stringArray1.Any(s => !stringArray2.Contains(s));

Answer 3

如果要检查一个数组的所有元素是否都存在于另一个数组中，或者可以使用val spark = SparkSession .builder .appName("test") .config("spark.local", "local[*]") .getOrCreate() spark.sparkContext.setCheckpointDir(path_checkpoint) val event1 = spark .readStream // .schema(schema_a) .option("header", "true") .option("sep", ",") .csv(path_a) val query = event1.writeStream .outputMode("append") .format("console") .start() spark.streams.awaitAnyTermination()函数，例如

，可以使用Linq All()函数

Any()

检查字符串数组1中的项是否存在于字符串数组2中并返回bool

代码：

3 个答案: