Question

我已经创建了一个菜单来调用不同的程序。我的第5个程序中也有一个菜单，可以执行不同的功能。

我想知道的是如何允许用户退出程序5并返回原始主菜单。好像我应该知道这个...

这是我的代码示例：

主菜单：

int main() {
while (true)
{
    system("cls");
    int option = menuOption();

    switch (option)
    {
    case 1: Program1(); break;
    case 2: Program2(); break;
    case 3: Program3(); break;
    case 4: Program4(); break;
    case 5: Program5(); break;
    default: return 0;
    }
    system("pause");
}
return 0;
}

程序5菜单：

void Program5() {
int score, selection;
string player;

while (true)
{
    system("cls");
    cout << "\n\t   Menu\n\t==========\n";
    cout << "1. Add a player and score\n";
    cout << "2. Show top 10 players & scores\n";
    cout << "3. Search for a player\n";
    cout << "4. Remove a player\n";
    cout << "5. Exit to main menu\n";
    cout << "\t==========\n";
    cout << "Option: \n";
    cin >> selection;
    cout << endl;

    switch (selection)
    {
    case 1:
        //Doesn't matter
    case 2:
        //Doesn't matter
    case 3:
        //Doesn't matter
    case 4:
        //Doesn't matter
    case 5:
        return;
        break;
    default: exit(1);
    }
    system("pause");
}
}

Answer 1

您应该删除@Html.EditorFor(model => model.EmailAddress, new { htmlAttributes = new { @class = "form-control width100", @required = "required" } })语句和system("pause");语句。您不想退出该程序。
之后，根据您的代码，它应该返回到default: exit(1);并进行while循环的另一次迭代以询问菜单选项。

Answer 2

返回后，您将返回主目录。例如，这段代码：

maxfunction = numpy.vectorize(lambda i: max(i,0.5))
print(maxfunction(currentGrid[newIndices]))

给出以下输出：

#include <iostream>

using namespace std;

void Program1(){

}

void Program2(){

}

void Program3(){

}

void Program4(){

}

void Program5(){
    int score, selection;
    string player;

    while (true)
    {
        system("cls");
        cout << "\n\t   Menu\n\t==========\n";
        cout << "1. Add a player and score\n";
        cout << "2. Show top 10 players & scores\n";
        cout << "3. Search for a player\n";
        cout << "4. Remove a player\n";
        cout << "5. Exit to main menu\n";
        cout << "\t==========\n";
        cout << "Option: \n";
        cin >> selection;
        cout << endl;

        switch (selection)
        {
        case 1:
            //Doesn't matter
        case 2:
            //Doesn't matter
        case 3:
            //Doesn't matter
        case 4:
            //Doesn't matter
        case 5:
            return;
            break;
        default: exit(1);
        }
        system("pause");
    }
}

int main(){
    while(true){
        cout << "In main():\n";
        int option;
        cin >> option;

        switch (option)
        {
        case 1: Program1(); break;
        case 2: Program2(); break;
        case 3: Program3(); break;
        case 4: Program4(); break;
        case 5: Program5(); break;
        default: return 0;
        }
    }
}

从另一个菜单返回菜单？

2 个答案: