Question

目标是向用户询问数字并返回总和，平均值，最小值和最大值。不使用函数如何获得最小值和最大值？

from cs50 import get_int

n= -1 
sum = 0
while n <= 1:
    n=get_int('Type an integer>1: ')
    print('read',n)

num_of_ints_to_be_read = n

while n >= 1:
    number = get_int('type an integer: ')
    sum += number
    n -= 1

print()
print()
print('The sum is ', sum)
print('The average is ', sum / num_of_ints_to_be_read)
print('The min is ', )
print('The max is ', )

#print()
#print()

#input('type anything to finish')

#Cant use functions for min and max

Answer 1

使用一个单独的变量来跟踪您读入的最小值和最大值，并且只有在找到新的最小值或最大值时才进行更新。请注意，我添加了一个新的导入math，以帮助确定最小值。

from cs50 import get_int
import math

n= -1 
sum = 0
min = math.inf #Set the initial min to infinity
max = 0
while n <= 1:
    n=get_int('Type an integer>1: ')
    print('read',n)

num_of_ints_to_be_read = n

while n >= 1:
    number = get_int('type an integer: ')
    if number > max:
        max = number
    if number < min:
        min = number
    sum += number
    n -= 1

print()
print()
print('The sum is ', sum)
print('The average is ', sum / num_of_ints_to_be_read)
print('The min is ', min)
print('The max is ', max)

Answer 2

要在python中复制最大功能，可以使用float('inf')：

if 5 < float('inf'):
    print('ok')

至少分钟：

if 5 > float('-inf'):
    print('ok')

如果要对一个数字列表进行最大限制，则可以使用for循环来实现：

def my_max(arr):  
    if not isinstance(arr, list) and not isinstance(arr, tuple): #type checking
        print (f'{arr} is not a list or tuple')
        return arr
    max_num = arr[0]
    for i in arr:
        if not isinstance(i, float) and not isinstance(i, int): #type checking
            print (f'{i} is not a number')
            return arr
        if i < float('inf') and i > max_num:
            max_num = i
    return max_num

print (my_max([1,5,6,7,2,3]))
# 7
print (my_max([1,5,'t',7,2,3]))
# t is not a number
print (my_max(4))
# 4 is not a list or tuple

如何在不使用Python函数的情况下找到最小值和最大值？

2 个答案: