Hibernate如何基于Albates或Random在数据库中创建列顺序？

Question

我使用XML配置，但是不知道休眠状态如何获取我的垂直实体字段？

   

   <property name="hibernate.dialect">org.hibernate.dialect.OracleDialect</property>
   <property name="hibernate.connection.driver_class">oracle.jdbc.driver.OracleDriver</property>
   <property name="hibernate.connection.url">jdbc:oracle:thin:@localhost:1521:db12c</property>
   <property name="hibernate.connection.username">simplehr2</property>
   <property name="hibernate.connection.password">12345</property>
   <property name="hibernate.show_sql">true</property>
   <property name="hibernate.connection.release_mode">auto</property>
   <property name="current_session_context_class">thread</property>
   <property name="hibernate.connection.autoReconnect">true</property>


   <mapping class="org.o7planning.tutorial.hibernate.entities.Department" />
   <mapping class="org.o7planning.tutorial.hibernate.entities.Employee" />
   <mapping class="org.o7planning.tutorial.hibernate.entities.SalaryGrade" />
   <mapping class="org.o7planning.tutorial.hibernate.entities.Timekeeper" />