Question

我刚学习python几个月，我正在尝试编写一个程序来帮助测试密码的特征。我已经很接近我需要的东西了，但是似乎有一行被跳过了，我不知道为什么...这是代码：

def main():

    print("Create a password. Password must follow these rules:")
    print("  - password must be at least 8 characters long")
    print("  - password must have one uppercase AND lowercase letter")
    print("  - password must have at least one digit")

    isValidPassword()

def isValidPassword():
    password = []
    password2 = []

    print()

    print("Enter password:", end="")
    pass1 = input("")    
    print("Re-enter password:", end="")
    pass2 = input("")

    password.append(pass1)
    password2.append(pass2)

    if password == password2 and len(password) >= 8 and password.isupper() == False and password.islower() == False and password.isalpha() == False and password.isdigit() == False:
        print("Password will work.")
    else:
        print("Password will not work. Try again.")
        isValidPassword()

main()

运行代码时，即使我输入了满足所有要求的密码，if语句下的打印语句（“ Password will work。”）也不会打印。我已经在def isValidPassword（）函数之外的另一个文件中运行了if语句，它似乎可以正常工作。

有人对它为什么行不通提供任何见解吗？？

Answer 1

我认为主要问题在于此处的比较：password == password2，因为您正在测试两个list对象是否相等。您应该做的是将输入存储为字符串，并测试字符串是否相等。

此代码应可以正常工作：

def isValidPassword():
    print("Enter password:", end="")
    password = input("")    
    print("Re-enter password:", end="")
    password2 = input("")

    if password == password2 and len(password) >= 8 and not password.isupper() and not password.islower() and not password.isalpha() and not password.isdigit():
        print("Password will work.")
    else:
        print("Password will not work. Try again.")
        isValidPassword()

Python是否有任何原因会跳过一行？

1 个答案: