我的解释如下。
BRDB.EXPORT SHIPMENT (table)
SHPMNT_REF | SHIPMENT_TYPE
867 | EHH
868 | EHH
869 | EHH
BRDB.EVENT_CODE (table)
FILE_NO | REMARKS EVENT_CODE
867 | TEST0 SIR
867 | TEST1 SIR
867 | TEST2 SIR
867 | TEST3 SIR
868 | TEST4 EEO
I want my report is showing as below
FILE NO | REMARKS
123 | TEST0,TEST1,TEST2
456 | TEST3
运行这些代码时,我收到了错误消息:“从只允许一列的子查询返回多列”。
select min(X.SHPMNT_REF) as "House B/L #",
listagg(case when SIR = 1 then X.REMARKS end, ',') within group (order by X.SHPMNT_REF) as "REMARKS(from SIR Event)"
FROM (select ES.SHPMNT_REF,
(select EE.REMARKS,
row_number() over (order by EE.FILE_NO)
FROM BRDB.EXPORT_EVENT EE
where EE.FILE_NO = ES.SHPMNT_REF
and EE.EVENT_CODE = 'SIR') as SIR
from BRDB.EXPORT_SHIPMENT ES)X
GROUP BY X.SHPMNT_REF
答案 0 :(得分:0)
假设您的示例输入由于错字而错了,这个简单的查询应该对您有用
SELECT file_no,
LISTAGG(remarks, ',') WITHIN GROUP (ORDER BY remarks) AS remarks
FROM brdb.event_code
WHERE event_code = 'SIR'
GROUP BY file_no
ORDER BY file_no;
答案 1 :(得分:0)
您的问题有以下问题,首先是第一部分EXPORT_SHIPMENT中的表名(我认为其中有下划线),而EVENT_CODE与您提供的代码段不匹配。您是否还在尝试将行号合并到“文件号”字段中?很难确定您要寻找什么。
对于原始错误,Oracle相关子查询不支持多列。这是导致该错误的原因,您可以返回ee.remarks
或row_number()
,不能同时返回两者。
select EE.REMARKS,
row_number() over (order by EE.FILE_NO)
from BRDB.EXPORT_EVENT EE
where EE.FILE_NO = ES.SHPMNT_REF
and EE.EVENT_CODE = 'SIR'
对于您想要的东西,我的最佳猜测是这样的,请注意,我在联接表时没有尝试子查询。
select X.FILE_NO
,listagg(X.REMARKS || ',') within group (order by X.SHPMNT_REF)
,listagg(X.ROW_NUM) within group (order by X.SHPMNT_REF)
FROM
(
select EE.FILE_NO,
ES.SHPMNT_REF,
EE.REMARKS,
row_number() over (order by EE.FILE_NO) as ROW_NUM
FROM EVENT_CODE EE
JOIN EXPORT_SHIPMENT ES
ON EE.FILE_NO = ES.SHPMNT_REF
AND EE.EVENT_CODE = 'SIR'
) X
group by X.FILE_NO