Question

我有这两个表：

产品具有一个地址

地址属于产品

当我想从一个城市寻找产品时，我会做：

Product.all.joins(:address).where(addresses: {city: @city})

当我想查找所有不区分大小写的城市

Address.all.where('lower(city) like ?', @city.downcase)

但是现在我要从另一个表中不区分大小写组合的记录。我该怎么办？

我尝试了一些方法，却一无所获：

Product.all.joins(:address).where(addresses: {"lower(city) like ?", @city.downcase})

给出错误：

SyntaxError: unexpected '}', expecting end-of-input
...ower(city) like ?", "new york"})
...

和另一种方式：

Product.all.joins(:address).where(addresses: {"lower(city) like ?": @city.downcase})

一无所获：

#<Product::ActiveRecord_Relation:0x3fb3fc142900>

obs：我提出了另一个问题，因为旧的错误地标记为重复。

Answer 1

Product.joins(:address).where "lower(addresses.city) like ?", @city.downcase

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不知道您在说什么“没有从地址表上的列城市进行跟踪”-“没有跟踪”是什么意思？

这是一个与您的模型进行的控制台会话，如上所述，显示了我的代码如上所述工作：

[14] pry(main)> Address.create city: "New York", product: Product.first
  Product Load (0.3ms)  SELECT  "products".* FROM "products" ORDER BY "products"."id" ASC LIMIT $1  [["LIMIT", 1]]
   (0.1ms)  BEGIN
  Address Create (43.9ms)  INSERT INTO "addresses" ("product_id", "city", "created_at", "updated_at") VALUES ($1, $2, $3, $4) RETURNING "id"  [["product_id", 1], ["city", "New York"], ["created_at", "2019-02-27 18:57:37.688063"], ["updated_at", "2019-02-27 18:57:37.688063"]]
   (0.3ms)  COMMIT
=> #<Address:0x00007fb1e4322178 id: 1, product_id: 1, city: "New York", created_at: Wed, 27 Feb 2019 18:57:37 UTC +00:00, updated_at: Wed, 27 Feb 2019 18:57:37 UTC +00:00>
[15] pry(main)> @city = "NEW YORK"
=> "NEW YORK"
[16] pry(main)> Product.joins(:address).where "lower(addresses.city) like ?", @city.downcase
  Product Load (0.7ms)  SELECT "products".* FROM "products" INNER JOIN "addresses" ON "addresses"."product_id" = "products"."id" WHERE (lower(addresses.city) like 'new york')
=> [#<Product:0x00007fb1e52f5e10 id: 1, name: "First Product", created_at: Wed, 27 Feb 2019 18:57:07 UTC +00:00, updated_at: Wed, 27 Feb 2019 18:57:07 UTC +00:00>]

从另一个不区分大小写的表中查找记录

1 个答案:

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