从location.hash中提取特定的参数值

Question

我具有以下位置的哈希值：

#/something/default
#/something/url1/user2
#/something/url2/url3/user3

仅提取{strong>之后的第一个参数值的正则表达式是什么，即我需要提取：something，default，{{ 1}}？

Answer 1

使用split并获取2nd数组值：

let str1 = '#/something/default'
let str2 = '#/something/url1/user2'
let str3 = '#/something/url2/url3/user3'
let str4 = '#/something'

console.log(str1.split('/')[2])
console.log(str2.split('/')[2])
console.log(str3.split('/')[2])

// You can use a fallback like this if there is no value:
console.log(str4.split('/')[2] || 'Nothing to see here')

但是，如果您对regexp有所了解，则可以使用以下方法：

const regexp = /^#\/.+?\/(.+?)(\/|$)/

let str1 = '#/something/default'
let str2 = '#/something/url1/user2'
let str3 = '#/something/url2/url3/user3'
let str4 = '#/something'

console.log(str1.match(regexp)[1])
console.log(str2.match(regexp)[1])
console.log(str3.match(regexp)[1])

// You can use a fallback like this if there is no value:
console.log((str4.match(regexp) || [])[1] || 'Nothing to see here')

Answer 2

此正则表达式可能会解决问题

(?<=#\/something\/)([^/\n]+)`