Question

以下是mongo查询

db.booking.aggregate(
                {$project:{
            date: {$dateToString: { format: "%Y-%m-%d", date: "$dispatchDate"}},officeId: "$fromBranchId",total:"$totalCharge"
        }},
        {$group: {
            _id: { date: "$date", officeId: "$officeId"},
            total: {$sum: "$total"}
        }},
        { $project: { bookings: { $concat: [ "$_id.date", ":",{ $convert: { input: "$total", to: "string" } } ]}}},
        {$group: {
             _id: {officeId: "$_id.officeId"},
             bookings: { $addToSet: "$bookings" }
         }}
        )

等效的Java代码是

Aggregation aggregation = newAggregation(
                match(Criteria.where(SessionManager.OPERATOR_ID).is(sessionManager.getOperatorId())),
                project().and(DateOperators.dateOf("dispatchDate").toString("%Y-%m-%d")).as("date").and("fromBranchId").as("officeId").and("totalCharge").as("total"),group("date","officeId").sum("total").as("total"),project().andExpression("concat(date,':', substr(total,0,-1))").as("bookings"), group("officeId").addToSet("bookings").as("bookings"));

我在执行===> group("officeId").addToSet("bookings").as("bookings") is invalid reference id 'officeId'.

时遇到的错误

所以请帮助我如何在Java {$group: {_id: {officeId: "$_id.officeId"},bookings: { $addToSet: "$bookings" }}}中执行这段代码在此先感谢：）

如何在Java中将数据分组时应用_id

0 个答案: