我想获取过去7天的每日总用户平均使用时间,我为每个用户编写了SQL的平均时间,但是现在我在LARAVEL SQL函数中有问题,请帮助修复此SQL。 / p>
$currentTime = Carbon::today();
$userUsage = DB::table('active_user')
->select(DB::raw('acu_name as name'),
DB::raw('u_fname as fname'),
DB::raw('AVG(TIMESTAMPDIFF(MINUTE,acu_at,acu_et)) as averageTime'),
DB::raw('count(*) as number'))
->join('u_info_one', 'active_user.acu_name', '=', 'u_info_one.u_email')
->whereDate('acu_at', '<=', $currentTime)
->groupBy('acu_name')
->get();
答案 0 :(得分:1)
您需要为此使用GROUP BY
,例如:
$userUsage = DB::table('active_user')
->select(DB::raw('acu_name as name'),
DB::raw('u_fname as fname'),
DB::raw('AVG(TIMESTAMPDIFF(MINUTE,acu_at,acu_et)) as averageTime'),
DB::raw('count(*) as number'))
->join('u_info_one', 'active_user.acu_name', '=', 'u_info_one.u_email')
->whereDate('acu_at', '<=', $currentTime)
->groupBy('acu_name', DB::raw('DATE(acu_at)'))
->get();
更新
如果您只需要所有用户的每日平均值,则可以从分组依据中删除acu_name
,例如:
$userUsage = DB::table('active_user')
->select(DB::raw('acu_name as name'),
DB::raw('u_fname as fname'),
DB::raw('AVG(TIMESTAMPDIFF(MINUTE,acu_at,acu_et)) as averageTime'),
DB::raw('count(*) as number'))
->join('u_info_one', 'active_user.acu_name', '=', 'u_info_one.u_email')
->whereDate('acu_at', '<=', $currentTime)
->groupBy(DB::raw('DATE(acu_at)'))
->get();
答案 1 :(得分:0)
正确答案是
$userUsage = DB::table('active_user')
->select(DB::raw('DATE(acu_at) as date'),
DB::raw('AVG(TIMESTAMPDIFF(MINUTE,acu_at,acu_et)) as averageTime'),
DB::raw('COUNT(DISTINCT `acu_name`) as users'))
->join('u_info_one', 'active_user.acu_name', '=', 'u_info_one.u_email')
->whereDate('acu_at', '<=', $currentTime)
->groupBy(DB::raw('DATE(acu_at)'))
->orderBy(DB::raw('DATE(acu_at)'))
->get();
foreach($userUsage as $usUa)
{
$avegTime = ($usUa->averageTime/$usUa->users);
echo "['".$usUa->date."',".$avegTime."],";
}