我正在尝试在一个函数内使用flextable::display()
函数,并使用display内该函数的参数。下面是我的功能:
add_footnote <- function(df, col, pattern, symbol){
tmp <- df
pat <- paste0(pattern, " {{x}}")
tmp <- display(tmp,
col_key = col,
i = ~ col == pattern,
pattern = pat,
formatters = list(x ~ as.character(symbol)),
fprops = list(x = fp_text(vertical.align = 'superscript')) )
return(tmp)
}
# Call function
df <- regulartable(head(iris))
add_footnote(df, col = 'Species', pattern = 'setosa', symbol = 'a')
我希望在a
列中出现setosa
的任何地方都获得上标Species
,但是它给出以下错误,指示显示函数看不到参数传递给函数:
eval(as.call(f [[2]]),envir = data)中的错误:找不到对象'pattern'
有人知道如何从函数中获取参数以供内部display()
函数识别吗?
答案 0 :(得分:2)
函数display
很难使用-这就是我编写flextable::compose
的原因。它可以依靠整洁的eval语法。以下2个示例可以为您提供帮助:
library(flextable)
library(officer)
library(rlang)
add_footnote_with_rlang <- function(df, col, pattern, symbol){
form_ <- sprintf("~ %s == '%s'", col, pattern)
colname <- enquo(col)
flextable::compose(
x = df, j = col, i = as.formula(form_),
value = as_paragraph(
as_chunk(!!colname),
as_chunk(symbol, props = fp_text(vertical.align = 'superscript')))
)
}
add_footnote <- function(df, col, pattern, symbol){
form_ <- sprintf("~ %s == '%s'", col, pattern)
flextable::compose(
x = df, j = col, i = as.formula(form_),
value = as_paragraph(
as_chunk(symbol, props = fp_text(vertical.align = 'superscript')))
)
}
# Call function
df <- regulartable(head(iris))
# df <- add_footnote(df, col = 'Species', pattern = 'setosa', symbol = 'a')
df <- add_footnote_with_rlang(df, col = 'Species', pattern = 'setosa', symbol = 'a')
df