Question

我正在使用primeng下拉列表，并且很难将我的对象出价到该下拉列表。确实会在下拉列表中填充空项目。.不确定如何指定字段名称。

HTML

<div class="form-group col-xs-3 col-md-3"
                                     [ngClass]="{
                                     'has-error':((ersaForm.get('costCenter').touched || ersaForm.get('costCenter').dirty ) && 
                                      !ersaForm.get('costCenter').valid) || (ersaForm.get('costCenter').value.cost_center_name == '')
                                     }">
 <label for="costCenterId" class="control-label">Cost Center</label>
 <p-dropdown [options]="iCostCenter" styleClass="form-control" formControlName="costCenter" placeholder="Cost Center (required)" id="costCenterId" name="costCenter"  dataKey="cost_center_id">
</p-dropdown>

对象

    {
  "result": [
    {
      "cost_center_id": 0,
      "cost_center_name": "0"
    },
    {
      "cost_center_id": 1,
      "cost_center_name": "1"
    },
    {
      "cost_center_id": 2,
      "cost_center_name": "2"
    },
}

TS

    export interface ICostCenter{

        cost_center_id: string,
        cost_center_name: string
    }

   iCostCenter: ICostCenter[];
    this._appParams.getAllCostCenters()
            .subscribe(
            data => {
                this.iCostCenter = data.result;

            }

Answer 1

如果您查看official documentation，则表示如果绑定到任意对象的集合，则需要使用optionLabel属性。

<p-dropdown [options]="iCostCenter" optionLabel="cost_center_name" styleClass="form-control" formControlName="costCenter" placeholder="Cost Center (required)" id="costCenterId" name="costCenter"  dataKey="cost_center_id">
</p-dropdown>

Answer 2

<p-dropdown [options]="iCostCenter" 
  optionLabel="cost_center_name" 
  styleClass="form-control" 
  formControlName="costCenter" 
  placeholder="Cost Center (required)" 
  id="costCenterId" 
  name="costCenter"
  dataKey="cost_center_id" 
  optionValue="costCenter>
</p-dropdown>

您可以使用 optionValue 将特定值设置为 formControl 而不是用于唯一标识选项中值的 Object.dataKey 属性。

具有反应形式的p-dropdown无法正确绑定

2 个答案: