我正在尝试在Python中模拟子字符串,但我收到错误:
length_message = len(update)
if length_message > 140:
length_url = len(short['url'])
count_message = 140 - length_url
update = update["msg"][0:count_message] # Substring update variable
print update
return 0
错误如下:
Traceback (most recent call last):
File "C:\Users\anlopes\workspace\redes_sociais\src\twitterC.py", line 54, in <module>
x.updateTwitterStatus({"url": "http://xxx.com/?cat=49s", "msg": "Searching for some ....... tips?fffffffffffffffffffffffffffffdddddddddddddddddddddddddddddssssssssssssssssssssssssssssssssssssssssssssssssssseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeedddddddddddddddddddddddddddddddddddddddddddddddfffffffffffffffffffffffffffffffffffffffffffff "})
File "C:\Users\anlopes\workspace\redes_sociais\src\twitterC.py", line 35, in updateTwitterStatus
update = update["msg"][0:count_message]
TypeError: string indices must be integers
我不能这样做?
update = update["msg"][0:count_message]
变量“count_message”返回“120”
给我一个线索。
最诚挚的问候,
我打这个电话,更新[“msg”]来自这里
x = TwitterC()
x.updateTwitterStatus({"url": "http://xxxx.com/?cat=49", "msg": "Searching for some ...... ....?fffffffffffffffffffffffffffffdddddddddddddddddddddddddddddssssssssssssssssssssssssssssssssssssssssssssssssssseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeedddddddddddddddddddddddddddddddddddddddddddddddfffffffffffffffffffffffffffffffffffffffffffffddddddddddddddddd"})
答案 0 :(得分:6)
您是否多次循环使用此代码?
如果是这样,也许第一次通过update
是一个字典,update["msg"]
返回一个字符串。细
但是你设置update
等于结果:
update = update["msg"][0:int(count_message)]
(大概)是一个字符串。
如果您正在循环播放,则下次循环时会出现错误,因为现在update
是一个字符串,而不是dict
(因此update["msg"]
不再有意义)
您可以通过在错误之前输入print语句来调试它:
print(type(update))
或者,如果不是太大,
print(repr(update))