Question

让我说我有两个向量：

vector1=c("name1","name2","name3")
vector2=c("#DAAD03","#301EE1","#5BD066")

我想遍历两个向量并打印以下行：

vector2[1] <- "#DAAD03" > name1
vector2[2] <- "#301EE1" > name2
vector2[3] <- "#5BD066" > name3

我尝试过：

for (i in vectors1){
  number=c(1)
  for (j in vectors2{
    print ("vectors2[",number,"] <- ",j, ">", i )
    number = number+1
  }
}

但不起作用。谢谢您的帮助

我收到以下错误：

> for (i in vectors1){
+   number=c(1)
+   for (j in vectors2{
Erreur : '{' inattendu(e) in:
"  number=c(1)
  for (j in vectors2{"
>     print ("vectors2[",number,"] <- ",j, ">", i )
Error in print.default("vectors2[", number, "] <- ", j, ">", i) : 
  objet 'j' introuvable
>     number = number+1
>   }
Erreur : '}' inattendu(e) in "  }"
> }
Erreur : '}' inattendu(e) in "}"
>

Answer 1

for (i in 1:length(vector1)){
  cat(paste0("vector2[",i,"] <- ","'",vector2[i],"'"," > ", vector1[i]))
}

 vector2[1] <- '#DAAD03' > name1
 vector2[2] <- '#301EE1' > name2
 vector2[3] <- '#5BD066' > name3

当心多余的循环，如果矩阵/向量大，它们将永远运行。

Answer 2

我认为您正在寻找这样的东西：

    for(i in 1:length(vector1)){
    print(paste(vector2[i],">",vector1[i]))}

输出：

    [1] "#DAAD03 > name1"
    [1] "#301EE1 > name2"
    [1] "#5BD066 > name3"

请注意，您也缺少几个括号，并且如果两个向量的长度相同，则不必使用多个循环。

遍历两个向量并使用R打印

2 个答案: