我是python的新手,我希望这段代码仅运行一次并停止运行,而不是每30秒运行一次
因为我想使用命令行每5秒使用不同的访问令牌运行这样的多个代码。 当我尝试这段代码时,它永远不会跳到第二个,因为它是有一段时间的:
import requests
import time
api_url = "https://graph.facebook.com/v2.9/"
access_token = "access token"
graph_url = "site url"
post_data = { 'id':graph_url, 'scrape':True, 'access_token':access_token }
# Beware of rate limiting if trying to increase frequency.
refresh_rate = 30 # refresh rate in second
while True:
try:
resp = requests.post(api_url, data = post_data)
if resp.status_code == 200:
contents = resp.json()
print(contents['title'])
else:
error = "Warning: Status Code {}\n{}\n".format(
resp.status_code, resp.content)
print(error)
raise RuntimeWarning(error)
except Exception as e:
f = open ("open_graph_refresher.log", "a")
f.write("{} : {}".format(type(e), e))
f.close()
print(e)
time.sleep(refresh_rate)
答案 0 :(得分:0)
据我了解,您正在尝试为多个访问令牌执行这段代码。为了简化您的工作,请将所有access_tokens
列为清单,并使用以下代码。它假定您事先了解所有access_tokens
。
import requests
import time
def scrape_facebook(api_url, access_token, graph_url):
""" Scrapes the given access token"""
post_data = { 'id':graph_url, 'scrape':True, 'access_token':access_token }
try:
resp = requests.post(api_url, data = post_data)
if resp.status_code == 200:
contents = resp.json()
print(contents['title'])
else:
error = "Warning: Status Code {}\n{}\n".format(
resp.status_code, resp.content)
print(error)
raise RuntimeWarning(error)
except Exception as e:
f = open (access_token+"_"+"open_graph_refresher.log", "a")
f.write("{} : {}".format(type(e), e))
f.close()
print(e)
access_token = ['a','b','c']
graph_url = ['sss','xxx','ppp']
api_url = "https://graph.facebook.com/v2.9/"
for n in range(len(graph_url)):
scrape_facebook(api_url, access_token[n], graph_url[n])
time.sleep(5)