Question

我已经使用Maps API创建了Google Map，现在我想找到最接近给定位置的n标记。我发现this Fiddle展示了如何找到最接近的单个标记，如何适应它以便找到最接近的n标记，而不仅仅是单个最接近的标记？

function find_closest_marker(event) {
    var distances = [];
    var closest = -1;
    for (i = 0; i < markers.length; i++) {
        var d = google.maps.geometry.spherical.computeDistanceBetween(markers[i].position, event.latLng);
        distances[i] = d;
        if (closest == -1 || d < distances[closest]) {
            closest = i;
        }
    }
    console.log('Closest marker is: ' + markers[closest].getTitle());
}

Answer 1

这不是有史以来最优雅的解决方案，但是假设原始源代码可以完成这项工作。

function find_closest_markers(event, n) {
    var markers_distances = [];
    for (i = 0; i < markers.length; i++) {
        var d = google.maps.geometry.spherical.computeDistanceBetween(markers[i].position, event.latLng);
        markers_distances[i] = {
            distance: d, 
            marker: markers[i]
        }
    }
    var closest_markers = markers_distances.sort((a, b) => {return a.distance-b.distance}).slice(0,n)
    return closest_markers.map((item) => {return item.marker})
}

Google Maps API-从位置获取n个最近的标记

1 个答案: