Question

如何确定个人热点是否处于活动状态？我尝试过：

    @objc   
    func getCurrentNetwork(_ resolve: RCTPromiseResolveBlock, rejecter reject: RCTPromiseRejectBlock)   
    {   
        var networkDict = [String : Any]()   
        let deviceName = UIDevice.current.name   
        print("device name: \(deviceName)")   
        guard let interfaces = CNCopySupportedInterfaces() as? [String] else {   
            reject("ios_errors", "Can't work on simulators", nil)   
            return   
        }   
        for interface in interfaces {   
            print("Looking up SSID info for \(interface)")   
            guard let interfaceInfo = CNCopyCurrentNetworkInfo(interface as CFString) else {   
                print("System error: \(interface) has no information") <- here   
                return   
            }   
            guard let networkInfo = (interfaceInfo as NSDictionary) as? [String: AnyObject] else {   
                print("System error: interface information is not a string-keyed dictionary")   
                return   
            }   
            for key in networkInfo.keys {   
                networkDict["\(key)"] = "\(networkInfo[key]!)"   
            }   
        }   
        resolve(networkDict)   
    }

当iPhone连接到公共热点时，以上示例将SSID名称（以及其他信息）返回给客户端。当我激活iPhone的个人热点时，我输入以下代码行：

print("System error: \(interface) has no information")
return

并返回客户而不得到热点的名称？

我在这里查看了2个选项：

detect hotspot enabling in iOS with private api's-私有api对我不好，因为我想将我的应用程序放在Apple商店中。
Swift - Get device's WIFI IP Address-通过这种方法，我想获取设备的wifi ip地址，如果它以172.20.10开头，则意味着个人热点已激活并且设备已连接至该设备，我可以返回设备名称作为SSID名称，但是这个问题不是很牢固，还是我错了？

获取个人热点状态（将由Apple批准）

0 个答案: