救救我! 我使用ajax弹出窗口成功保存了数量,但是我想在弹出窗口中隐藏2个按钮
单击保存按钮->保存 当您单击保存关闭->不保存
我的jquery ajax
url = '/admin/stocktaking/index/save';
// ajax
jQuery.ajax({
url: url,
dataType: 'json',
type : 'post',
data: {sku: sku,qty: stocktaking},
showLoader: true,
success: function(data) {
console.log(data);
if (stocktaking >= 0) {
if (data.success) {
//popup success
var popup = $('<div class="themecafe-free-popup"/>').html(data.success).modal({
modalClass: 'changelog',
buttons: [{
text: 'Close',
click: function () {
this.closeModal();
}
},{
text: 'Save',
click: function () {
location.href = "/admin/stocktaking/index/save";
return false;
}
}]
});
popup.modal('openModal');
//end popup success
//popup error
} else if (data.error) {
var popup = $('<div class="themecafe-free-popup"/>').html(data.error).modal({
modalClass: 'changelog',
buttons: [{
text: 'Close',
click: function () {
this.closeModal();
}
}]
});
popup.modal('openModal');
//end popup error
}
}
}
});
答案 0 :(得分:0)
尝试删除以下代码块,然后按钮应该消失。
buttons: [{
text: 'Close',
click: function () {
this.closeModal();
}
},{
text: 'Save',
click: function () {
location.href = "/admin/stocktaking/index/save";
return false;
}
}]