Question

我有一个部件集合

{
  "_id": {
    "$oid": "5c735f7fbc162b1ee5cdacca"
  },
  "@pno": "10701",
  "pname": "When Harry Met Sally",
  "qoh": "120",
  "price": "19.99",
  "level": "30"
}

和订单集合

{
  "_id": {
    "$oid": "5c735fcebc162b1ee5cdaf1a"
  },
  "@ono": "1022",
  "@takenBy": "1001",
  "@customer": "2222",
  "receivedDate": "1995-02-13",
  "shippedDate": "1995-02-20",
  "items": {
    "item": [
      {
        "partNumber": "10601",
        "quantity": "1"
      },
      {
        "partNumber": "10701",
        "quantity": "1"
      }
    ]
  }
}

所以问题是如何通过查询这两个集合来显示每个客户订购的零件名称（pname）（如何将零件中的@pno与订单中的partNumber相匹配）？谢谢！

Answer 1

              {$unwind:{
                        path:"$items.item",
                        preserveNullAndEmptyArrays:true
             }},

         {
           $lookup: {
            from: "Parts",
            localField: "items.partNumber",
            foreignField: "pno",
            as: "partsDetails"
          }
        },

可以将其分组。

Answer 2

您应该使用查找聚合运算符。 https://docs.mongodb.com/manual/reference/operator/aggregation/lookup/

db.getCollection('Parts').aggregate([
    {$unwind:"$items.item"},
    {
      $replaceRoot: { newRoot: { $mergeObjects: [ "$$ROOT","$items.item" ] } }
    },      
    {$lookup:
        {
            from: "Details",
            localField: "partNumber",
            foreignField: "@pno",
            as: "partTitle"
        }
    },
    { $project: { items: 0 } },
    {
      $replaceRoot: { 
        newRoot: { $mergeObjects: [ "$$ROOT",{$arrayElemAt:["$partTitle",0]} ] } 
    }
    },     
    { $project: { partTitle: 0 } },
]);

结果：

{
    "_id" : ObjectId("5c735f7fbc162b1ee5cdacca"),
    "@ono" : "1022",
    "@takenBy" : "1001",
    "@customer" : "2222",
    "receivedDate" : "1995-02-13",
    "shippedDate" : "1995-02-20",
    "partNumber" : "10701",
    "quantity" : "1",
    "@pno" : "10701",
    "pname" : "When Harry Met Sally",
    "qoh" : "120",
    "price" : "19.99",
    "level" : "30"
}

如何查询MongoDB的多个集合？

2 个答案: