我可以使表示为简单要素几何的形状变形。我需要对存储为标准x,y数据框的形状执行相同的操作。
为什么x,y数据框方法对我不起作用?
使用简单功能-可以正常运行
library(tidyverse)
library(gganimate)
library(transformr)
star1 <- sf::st_sfc(poly_star(n = 7, st = TRUE))
circle1 <- sf::st_sfc(poly_circle(st = TRUE))
df1 <- data.frame(
id = c(1),
geo = c(star1)
)
df2 <- data.frame(
id = c(1),
geo = c(circle1)
)
morph <- tween_sf(df1, df2,
ease = 'linear',
nframes = 12,
id = id)
ani <- ggplot(morph) +
geom_sf(aes(geometry = geometry)) +
transition_time(time = .frame) +
theme(legend.position = "none")
show <- animate(ani, nframes = 30, fps = 30,
renderer = gifski_renderer(loop = FALSE), start_pause = 15)
show
使用x,y数据框-变形已损坏
library(tidyverse)
library(gganimate)
library(transformr)
library(tweenr)
star7 <- poly_star(n = 7, st = FALSE)
star10 <- poly_star(n = 10, st = FALSE)
morph <- tween_state(star7, star10,
ease = 'linear',
nframes = 12,
id = id)
ani <- ggplot(morph) +
geom_polygon(aes(x = x, y = y, group = id)) +
transition_time(time = .frame) +
theme(legend.position = "none")
show <- animate(ani, nframes = 30, fps = 30,
renderer = gifski_renderer(loop = FALSE), start_pause = 15)
show
答案 0 :(得分:0)
我想找的是
morph <- tween_polygon(star7, star10,
ease = 'linear',
nframes = 12,
id = id)