无法将django对象传递到有角度的前端

时间:2019-02-25 01:11:45

标签: python django angular

我正在使用Django 2.1.5和Angular 7.3.1。我有一个Django后端类DetailView,我正尝试使用该类将对象传递给Angular前端。我知道DetailView运行良好,因为使用Django渲染模板时可以看到该对象。由于某种原因,我似乎无法通过Django API将其传递给Angular。

当我加载页面时,dogdetail上没有任何显示,并且控制台显示错误:DogdetailComponent.html:2 ERROR TypeError: Cannot read property 'name' of undefined at Object.eval [as updateRenderer]

我已经尝试了几种变体和语法等。我认为,如果Django API正确获取了对象,那么Angular应该可以从API端点提取它。

我使用Postman访问API端点http://127.0.0.1:8000/1/dogdetail/,获得了dog对象,并且可以访问其属性。

我的django urls.py:

from django.urls import path
from .views import DogList, DogDetailDjango, index

urlpatterns = [
    path('', index, name='index'),
    path('dogs/', DogList.as_view(), name='doglist'),
    path('<int:pk>/dogdetail/', DogDetailDjango.as_view(), name='dogdetail'),
]

dogdetail.component.ts:

import { Component, OnInit } from '@angular/core';
import { ApiService } from '../api.service'
import { Dog } from '../dog'


@Component({
  selector: 'app-dogdetail',
  templateUrl: './dogdetail.component.html',
  styleUrls: ['./dogdetail.component.scss']
})

export class DogdetailComponent implements OnInit {

  dogdetail : Dog[];

  constructor(private apiservice: ApiService) { }

  ngOnInit() {
    this.getDog();
  }

    getDog(): void {
      this.apiservice.getDogDetail().subscribe(dogdetail=> this.dogdetail = dogdetail)
      console.log(this.dogdetail);
  }

}

api.service.ts

import { Injectable } from '@angular/core';
import { HttpClient, HttpHeaders } from "@angular/common/http"
import { DogListComponent } from './dog-list/dog-list.component';
import { Dog } from './dog'
import { Observable, of } from 'rxjs'


@Injectable({
  providedIn: 'root'
})
export class ApiService {

  apiURL: string = 'http://127.0.0.1:8000'

  constructor(private httpClient: HttpClient) { }


  public getDogDetail(): Observable<Dog[]> {
    return this.httpClient.get<Dog[]>(`${this.apiURL}/1/dogdetail`);
}
}

dogdetail视图Django:

class DogDetailDjango(DetailView):
    model = Dog
    serializer_class = DogSerializer
    template_name = 'detail.html'

dogdetail.component.html

dogdetail works!

    {{ dogdetail }}


    <h1>{{ dogdetail.name }} </h1>

1 个答案:

答案 0 :(得分:0)

@SimonK的答案正确,在安装适用于Google chrome的CORS插件后,我只能摆脱错误。我首先尝试创建正确的标题和所有内容,但只有在安装了插件之后,我才停止出现错误,因此无法正常工作。