Question

我想将WordPress API的JSON响应与Python的库请求连接在一起。这是我的代码：

import requests
results = []
pagination = 1
url = 'https://example.com/wp-json/wp/v2/posts?after=2019-01-01T00:00:00&before=2019-02-01T00:00:00&per_page=5&page={}'.format(pagination)
r = requests.get(url)
data = r.json()
for i in data:
    results.append(i)
while r.status_code == 200:
    pagination += 1
    r = requests.get(url)
    data = r.json()
    for i in data:
        results.append(i)
    else:
        break
print(results)

我只停留在第一页。

Answer 1

您在初始设置URL格式时绑定了该值，此值将不再更新。

传递某些params as a dictionary to requests而不是传递URL可能更容易，并且每次迭代都进行分页更新，例如：

import requests
results = []
pagination = 1
url = 'https://example.com/wp-json/wp/v2/posts?after=2019-01-01T00:00:00&before=2019-02-01T00:00:00'
params = {'per_page': 5, 'page': pagination}
r = requests.get(url, params=params)
data = r.json()
for i in data:
    results.append(i)
while r.status_code == 200:
    pagination += 1
    params.update({'page': pagination})
    r = requests.get(url, params=params)
    data = r.json()
    for i in data:
        results.append(i)
    else:
        break
print(results)

将JSON分页响应与python请求连接起来

1 个答案: