Question

在这里，我正在创建将数据插入数据库的出勤表单击提交按钮后。数据的插入基于2 单选按钮不存在/存在，问题出在单击提交之后按钮，除下拉按钮外，其他组件也可以正常工作下拉按钮仅插入一个字符串而不是服务时间顺便说一句，我在数据库中将服务时间声明为varchar，所以我是确信不是导致错误的数据库。也许有人可以帮助我，非常感谢。预先谢谢你
在此处输入代码

<?php
include("Sampledb.php");
include("Sample.php");
$flag=0;
if(isset($_POST['submit']))
{
    foreach($_POST['attendance_status'] as $id1=>$attendance_status)
        {
        $name=$_POST['name'][$id1];
        $id=$_POST['id'][$id1];
        $date=date("Y-m-d H:i:s");  
        $servicetime=$_POST['servicetime'][$id1];


        $result=mysqli_query($objconn,"insert into 
        attendrecord(id,name,attendance_status,attendance_date,servicetime)

        values('$id','$name','$attendance_status','$date','$servicetime')");            
            if($result)
            {
                $flag=1;
            }                   

        }
    header("Location:sampleindex.php");
    exit;
}
?>

<div class="panel panel-default">
<div class="panel panel-heading">

<form action="sampleindex.php" method="Post"> 

<label>Service time:</label>
<select name="servicetime">
<option>00:00</option>
<option value="7:30-9:30">7:30-9:30</option>
<option value="10:30-12:30">10:30-12:30</option>
<option value="1:30-3:30">1:30-3:30</option>
<option value="4:30-6:30">4:30-6:30</option>
</select>

<a class="btn btn-info pull-right" href="view.php">View all<a/>


</div>
</div> 

<div id="alert" style="display:none;" class="alert alert-success" ">
<a href="#" class="close" data-dismiss="alert">&times;</a>
<strong>Success!</strong>Save
</div>

<h3>
<div class="well text-center">Date:<?php echo date("Y-m-d"); ?> </div>
</h3>

<div class="panel panel-body">


<tr>
<table class="table table-striped">
</tr>

<th>ID Number</th><th>Member Name</th><th>Attendace Status</th> 
<?php $result=mysqli_query($objconn,"select* from attend");
$id = 0;
$counter=0;
while($row=mysqli_fetch_array($result))
{
$id++;
?>


<tr>
<td><?php echo $row['id']; ?></td>
<input type="hidden" value="<?php echo $row['id']; ?>"name="id[]">
<td><?php echo $row['name']; ?></td>
<input type="hidden" value="<?php echo $row['name']; ?>"name="name[]">
<td> 
<input type="radio" name="attendance_status[<?php echo $counter; ?>]" 
value="present">Present
<input type="radio" name="attendance_status[<?php echo $counter; ?>]" 
value="absent">Absent
</td>
</tr>   
<?php
$counter++;
}

?>
</table>    

<input type="submit" name="submit" value="submit" onclick="return mess();">

</div>

<script type="text/javascript">
function mess()
{
    if($flag=1){
    alert ("Record Save!");
    return true;}
    else
    alert ("Record Not Save!");
}
</script>
<script type="text/javascript">
$(document).ready(function(){
    $('#submit').click(function(){
        $('#alert').css('display','block');
    });
});
</script>
</div>  
</div>

Answer 1

您的服务时间不是一个数组，因为它对所有记录都相同。因此，您需要按如下所示更改PHP代码：

$servicetime=$_POST['servicetime'];

希望它对您有帮助。

Answer 2

使用$_POST['servicetime'][$id]代替$_POST['servicetime']

如何使用带foreach循环的下拉菜单在数据库中插入数据

2 个答案: