我有一个无法跟踪的错误。我是新来的,如果在搜索中错过了此内容,对不起,但是我尝试了几件事,没有运气。
UserApi.java:
public ActionResult addEditProduct()
{
return View();
}
[HttpPost]
public ActionResult addEditProduct(EditProductModel model)
{
if (!model.HasCategories)
{
ModelState.AddModelError(string.Empty, "A category is required.");
return View(new { id = model.P.ID });
}
if (!ModelState.IsValid())
{
return View(new { id = model.P.ID });
}
}
UserRepository.java:
package com.jsp.jsp;
import com.jsp.models.User;
import com.jsp.services.UserService;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.RequestParam;
import org.springframework.web.bind.annotation.RestController;
@RestController
class UserApi {
private final UserService userService;
public UserApi(UserService userService) {
this.userService = userService;
}
@RequestMapping(value="/api/user", method=RequestMethod.POST)
public User createUser(
@RequestParam(value="name", required=true) String name,
@RequestParam(value="email", required=true) String email,
@RequestParam(value="password", required=true) String password,
@RequestParam(value="confirm", required=true) String confirm)
{
User u = this.userService.createUser(new User(name, email, password));
return u;
}
}
Server.java
package com.jsp.repositories;
import org.springframework.stereotype.Repository;
import java.util.List;
import java.util.Optional;
import com.jsp.models.User;
import org.springframework.data.repository.CrudRepository;
@Repository
public interface UserRepository extends CrudRepository<User, Long> {
List<User> findByEmail(String email);
Optional<User> findById(Long id);
List<User> findAll();
}
UserService.java
package com.jsp.jsp;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
// import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RestController;
@SpringBootApplication(scanBasePackages={"com.jsp.models","com.jsp.repositories","com.jsp.services"})
@RestController
public class Server {
public static void main(String[] args) {
SpringApplication.run(Server.class, args);
}
}
pom.xml
package com.jsp.services;
import java.util.List;
import com.jsp.models.User;
import com.jsp.repositories.UserRepository;
import org.springframework.stereotype.Service;
@Service
public class UserService {
private final UserRepository userRepository;
public UserService(UserRepository userRepository) {
this.userRepository = userRepository;
}
public List<User> allUsers() {
return this.userRepository.findAll();
}
public User createUser(User u) {
return this.userRepository.save(u);
}
}
因此,简而言之,当我在VSCode中运行上述项目时,出现以下错误:
2019-02-23 19:07:52.744 WARN 25412 --- [restartedMain] ConfigServletWebServerApplicationContext:遇到异常 在上下文初始化期间-取消刷新尝试: org.springframework.beans.factory.UnsatisfiedDependencyException: 在文件中定义名称为“ userService”的bean创建时出错 [C:\ Users \ Alex \ Documents \ dojo \ javatown \ everything \ target \ classes \ com \ jsp \ services \ UserService.class]: 通过构造函数参数0表示的不满足的依赖关系; 嵌套异常为 org.springframework.beans.factory.NoSuchBeanDefinitionException:否 类型为“ com.jsp.repositories.UserRepository”的合格Bean 可用:至少有1个符合自动装配条件的bean 候选人。依赖项注释:{}
我的理解是,我创建的存储库应该自动转换为Bean,然后将其自身连接到我创建的服务。但是,这似乎没有发生。我的示例视频使用MySQL-会有所作为吗?我在为Postgres 11使用正确的驱动程序吗?我迷路了。
答案 0 :(得分:1)
一些评论和建议:
1。在构造函数上添加自动装配的注释,可以更清楚地了解Spring需要做什么。
@Autowired
public UserService(UserRepository userRepository) {
this.userRepository = userRepository;
}
2。我不理解您的主类上的@RestController注释。
@SpringBootApplication(scanBasePackages {"com.jsp.models","com.jsp.repositories","com.jsp.services"})
@RestController --> THIS CAN BE REMOVED
public class Server {
public static void main(String[] args) {
SpringApplication.run(Server.class, args);
}
}
3。您应该在Spring Boot应用程序上添加@EnableJpaRepositories(“ com.jsp.repositories”)=>它会扫描该软件包中的存储库。
@SpringBootApplication(scanBasePackages {"com.jsp.models","com.jsp.repositories","com.jsp.services"})
@EnableJpaRepositories("com.jsp.repositories")
public class Server {
public static void main(String[] args) {
SpringApplication.run(Server.class, args);
}
}