我正在尝试使用敲除js在asp .net mvc 5中上传图像,并且类型为HttpPostedFileBase的paraFrame PhotoFile变为null,并且我无法上传图像,我是使用Knockout js的新工作想要有人帮助我,
这是模型,
public int LenderId { get; set; }
public string GenderId { get; set; }
public string GenderName { get; set; }
public string Email { get; set; }
public bool IsActive { get; set; }
public string PhotoPath { get; set; }
public HttpPostedFileBase PhotoFile { get; set; }
这是html
<div class="form-group">
<span class="control-label col-md-2"><strong>Foto:</strong></span>
<div class="col-md-10">
<span class="btn btn-default btn-file">
<input type="file" class="form-control" id="PhotoUpload" name="PhotoUpload" data-bind="attr:{src: PhotoPath}" />
</span>
</div>
</div>
这是js
function lenderModel(){ var lenderModel = this;
lenderModel.LenderId = ko.observable();
lenderModel.FirstName = ko.observable();
lenderModel.MiddleName = ko.observable();
lenderModel.FirstLastName = ko.observable();
lenderModel.SecondLastName = ko.observable();
lenderModel.IdentificationCard = ko.observable();
lenderModel.GenderId = ko.observable();
lenderModel.GenderName = ko.observable();
lenderModel.Email = ko.observable();
lenderModel.IsActive = ko.observable();
lenderModel.PhotoPath = ko.observable();
lenderModel.CreateBy = ko.observable();
lenderModel.CreationDate = ko.observable();
lenderModel.ModifiedBy = ko.observable();
lenderModel.ModifiedDate = ko.observable();
}
lenderViewModel.Create = function () {
if (lenderViewModel.IsNew()) {
$.ajax({
url: '/AdminLenders/Create',
data: ko.toJSON(lenderViewModel.LenderModel()),
dataType: "json",
type: "POST",
contentType: "application/json; charset=utf-8",
async: true,
success: function (data) {
if (data.Success) {
LoadGenders();
LoadListLenders();
$('#TextboxFirstName').val('');
$('#TextboxMiddleName').val('');
$('#TextboxFirstLastName').val('');
$('#TextboxSecondLastName').val('');
$('#TextboxIdentificationCard').val('');
$('#TextboxEmail').val('');
$('#ComboBoxGenders').val('');
$('#TextboxIsActive').prop('checked', false);
swal("Prestamista creado!", "Se ha registrado correctamente!", "success")
}
else {
swal("Error creando el prestamista!", data.Data, "error")
}
},
error: function (ex) {
alert('Ocurrión un error');
}
});
}
};
由于我对敲除js还是陌生的,所以我不知道如何实现它,帮助欣赏自己的贡献和帮助
答案 0 :(得分:2)
我猜测了控制器上的Create
方法是什么样的,并使用FormData对象提出了这个方法。
lenderViewModel.Create = function () {
if (lenderViewModel.IsNew()) {
var lender = lenderViewModel.LenderModel();
var lenderData = new FormData();
// Build up a matching Lender
lenderData.append("LenderId", lender.LenderId());
lenderData.append("GenderId", lender.GenderId());
lenderData.append("GenderName", lender.GenderName());
lenderData.append("Email", lender.Email());
lenderData.append("IsActive", lender.IsActive());
lenderData.append("PhotoPath", lender.PhotoPath());
// Get the file and add it to the Lender
var fileUpload = $("#PhotoUpload").get(0);
var files = fileUpload.files;
if(files.length === 1) {
lenderData.append("PhotoFile", files[0]);
}
$.ajax({
url: '/AdminLenders/Create',
data: lenderData,
enctype: "multipart/form-data",
dataType: "json",
type: "POST",
contentType: false,
processData: false,
success: function (data) {
if (data.Success) {
LoadGenders();
LoadListLenders();
$('#TextboxFirstName').val('');
$('#TextboxMiddleName').val('');
$('#TextboxFirstLastName').val('');
$('#TextboxSecondLastName').val('');
$('#TextboxIdentificationCard').val('');
$('#TextboxEmail').val('');
$('#ComboBoxGenders').val('');
$('#TextboxIsActive').prop('checked', false);
swal("Prestamista creado!", "Se ha registrado correctamente!", "success")
}
else {
swal("Error creando el prestamista!", data.Data, "error")
}
},
error: function (ex) {
alert('Ocurrión un error');
}
});
}
};