Question

我需要制作一个获取随机字符并检查其ASCII值（int）的程序。

例如：

Console.WriteLine("Please enter your first character");

char num1 = int.char(Console.ReadLine());

if((character) >= 65 && (character) <= 90 && (character) >= 97 && (character) <= 122)
{
    letters += 1;
}

该程序会像检查数字一样检查值，例如，如果我输入字母 F ，它将不会在字母计数器中加1。

Answer 1

尝试一下

Console.WriteLine("Please enter your first character");
char num1 = int.char(Console.ReadLine());
if(((character) >= 65 && (character) <= 90) || ((character) >= 97 && (character) <= 122))
{
    letters += 1;
}

您在AND-OR逻辑中犯了一个小错误。

Answer 2

您可以尝试以下代码；

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ConsoleApp1
{
    class Program
    {
    static void Main(string[] args)
    {
        Console.WriteLine("Please enter how many characters your password will have");
        int num1 = int.Parse(Console.ReadLine());
        int letters = 0;
        int numbers = 0;
        for (int i = 0; i < num1; i++)
        {
            Console.WriteLine("Please enter the character");
            char character = char.Parse(Console.ReadLine());
            if (character >= 'A' && character <= 'Z' || character >= 'a' && character <= 'z')
            {
                letters += 1;
            }
            if(character >= '0' && (int)character <= '9')
            {
                numbers += 1;
            }
            if (character <= 'A' && character >= 'Z' || character <= 'a' && character >= 'z' || character <= '0' && (int)character >= '9')
            {
                Console.WriteLine("you have entered invalid character");
            }
        }
        if(letters >= numbers)
        {
            Console.WriteLine("The password has " + num1 + " characters and its legal");
        }
        else
        {
            Console.WriteLine("The password has " + num1 + " characters and it is illegal");
        }
        Console.ReadLine();
    }
}
}

检查不同字符的ASCII值

2 个答案: