Question

SELECT 
    A.DJ_NUMBER as djNo
    ,MAX(A.ACTION) as 'SetupStarted'
    ,MIN(A.ACTION_TIME) AS 'SetupStart'
    ,MAX(B.ACTION) as 'RunStarted'
    ,MAX(B.ACTION_TIME) AS 'UpTimeStart'
    ,MAX(C.ACTION) as 'RunEnded'
    ,MAX(C.ACTION_TIME) AS 'UpTimeEnd'
    ,FORMAT(DATEDIFF(SECOND, MAX(A.ACTION_TIME), MAX(B.ACTION_TIME))/60.0,'##.##') AS Setup
    ,FORMAT(DATEDIFF(SECOND, MAX(B.ACTION_TIME), (C.ACTION_TIME))/60.0, '##.##') AS UpTime  
FROM 
    [AFL_MES2O_Interface_Data_arch] A, 
    [StagingDB].[dbo].[AFL_MES2O_Interface_Data_arch] B, 
    [StagingDB].[dbo].[AFL_MES2O_Interface_Data_arch] C
--WHERE (B.DJ_NUMBER = A.DJ_NUMBER AND MAX(B.ACTION_TIME) > Min(A.ACTION_TIME)) and (C.DJ_NUMBER = B.DJ_NUMBER AND MAX(C.ACTION_TIME) > MAX(B.ACTION_TIME)) 
GROUP BY  
    A.DJ_NUMBER 
HAVING 
    (B.DJ_NUMBER = A.DJ_NUMBER 
     AND MAX(B.ACTION_TIME) > Min(A.ACTION_TIME)) 
    AND (C.DJ_NUMBER = B.DJ_NUMBER 
         AND MAX(C.ACTION_TIME) > MAX(B.ACTION_TIME))
ORDER BY 
    SetupStart ASC, UpTimeEnd

这是我遇到的错误：

信息8121，第16级，状态1，第15行
  在HAVING子句中，“ StagingDB.dbo.AFL_MES2O_Interface_Data_arch.DJ_NUMBER”列无效，因为它不在聚合函数或GROUP BY子句中。

信息8121，第16级，状态1，第15行
  在HAVING子句中，“ StagingDB.dbo.AFL_MES2O_Interface_Data_arch.DJ_NUMBER”列无效，因为它不在聚合函数或GROUP BY子句中。

信息8121，第16级，状态1，第15行
  在HAVING子句中，“ StagingDB.dbo.AFL_MES2O_Interface_Data_arch.DJ_NUMBER”列无效，因为它不在聚合函数或GROUP BY子句中。

Answer 1

旧式联接的最大问题之一是您将联接条件与查询的过滤逻辑混合在一起，因为您将它们都放在了where子句中。在这里，您试图将所有这些都放在where子句中，但遇到一个错误，即聚合可能不会出现在where中，但应该出现在having中，并且将所有条件都移到了having只是为了获得上述错误。因此，要解决此问题，请将连接条件保留在where子句中：

WHERE (B.DJ_NUMBER = A.DJ_NUMBER) and (C.DJ_NUMBER = B.DJ_NUMBER)

和having中的聚合：

HAVING (MAX(B.ACTION_TIME) > Min(A.ACTION_TIME)) and (MAX(C.ACTION_TIME) > MAX(B.ACTION_TIME))

正如其他人在评论中所建议的那样，您实际上应该停止使用旧样式的联接。用[inner join][1]重写查询：

FROM 
    [AFL_MES2O_Interface_Data_arch] A
    inner join [StagingDB].[dbo].[@AFL_MES2O_Interface_Data_arch] B on B.DJ_NUMBER = A.DJ_NUMBER
    inner join [StagingDB].[dbo].[@AFL_MES2O_Interface_Data_arch] C on C.DJ_NUMBER = B.DJ_NUMBER

在这种情况下，您将不再需要where子句，您将在having中写入聚合，如上所示。

此外，您的UpTime子句的select表达式中有一个错误-无法C.ACTION_TIME这样保留。它应该在聚合函数中，例如MAX(C.ACTION_TIME)。

Answer 2

我明白了。解决方法如下：

                SELECT 

                     A.DJ_NUMBER    AS JobNo
                    ,MAX(A.ACTION) as SetupStarted
                    ,MIN(A.ACTION_TIME) AS SetupStart     
            --      ,MAX(A.ACTION_TIME) AS 'SetupStartEnd'
                    ,MAX(B.ACTION) as RunStarted
            --      ,MIN(B.ACTION_TIME) as 'RunStarted' 
                    ,MAX(B.ACTION_TIME) AS UpTimeStart
                    ,MAX(C.ACTION) as 'RunEnded'
            --      ,MIN(C.ACTION_TIME) as 'UpTimeEndStart'
                    ,MAX(C.ACTION_TIME) AS UpTimeEnd 
                    ,FORMAT(DATEDIFF(SECOND, MIN(A.ACTION_TIME), MAX(B.ACTION_TIME))/60.0,'##.##') AS Setup
                    ,FORMAT(DATEDIFF(SECOND, MAX(B.ACTION_TIME), MAX(C.ACTION_TIME))/60.0,'##.##') AS UpTime    

            FROM
                    [StagingDB].[dbo].[AFL_MES2O_Interface_Data_arch] as A
                    INNER JOIN [StagingDB].[dbo].[AFL_MES2O_Interface_Data_arch] as B
                            ON (B.DJ_NUMBER = A.DJ_NUMBER  AND A.ACTION_TIME IS NOT NULL) AND B.ACTION_TIME > A.ACTION_TIME
                    INNER JOIN [StagingDB].[dbo].[AFL_MES2O_Interface_Data_arch] as C
                            ON (C.DJ_NUMBER = B.DJ_NUMBER  AND B.ACTION_TIME IS NOT NULL) AND C.ACTION_TIME > B.ACTION_TIME 
            GROUP BY  A.DJ_NUMBER
            --ORDER BY SetupStart ASC, UpTimeEnd ASC
            --where TubeJobNo = 20738056

有关查询代码以及查询代码在何处的问题

2 个答案: